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daisydukeee

  • one year ago

Can someone help me please?

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  1. Foxracer62
    • one year ago
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    yes

  2. daisydukeee
    • one year ago
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    Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credit. \[x ^{2} + 2x + y ^{2} + 4y = 20\]

  3. daisydukeee
    • one year ago
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    This is what I have so far x² + 2x + y² + 4y = 20 (x² + 2x) + (y² + 4y) = 20 (x² + 2x+1) + (y² + 4y+4) = 20 + (1 + 4) (x² + 2x+1) + (y² + 4y+4) = 25

  4. Foxracer62
    • one year ago
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    k give me a sec to solve

  5. daisydukeee
    • one year ago
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    I have been using this for the steps. I'm on step 4, but I can't quite seem to figure out how to "factor each quadratic".

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  6. Foxracer62
    • one year ago
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    ok so take the question and type it into mathway (mathway.com) it will give you the answer and the steps

  7. daisydukeee
    • one year ago
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    Okay, I will try that. Thanks.

  8. Foxracer62
    • one year ago
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    Medal?

  9. anonymous
    • one year ago
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    you can really go right to the answer without all that rigamarole

  10. anonymous
    • one year ago
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    \[x ^{2} + 2x + y ^{2} + 4y = 20\] half of 2 is 1, \(6^2=1\) half of 4 is 2, \(2^2=4\) go right from there to \[(x+1)^2+(y+2)^2=20+1+4\]

  11. anonymous
    • one year ago
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    oops i meant "\(1^2=1\)"

  12. daisydukeee
    • one year ago
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    Oh okay, so the center would be (1,2) and the radius would be 5?

  13. anonymous
    • one year ago
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    no

  14. anonymous
    • one year ago
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    the radius is 5, that is correct

  15. anonymous
    • one year ago
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    center is \((-1,-2)\)

  16. daisydukeee
    • one year ago
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    Ah gotcha. I get it. Thank you!

  17. anonymous
    • one year ago
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    yw

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