daisydukeee
  • daisydukeee
Can someone help me please?
Geometry
schrodinger
  • schrodinger
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Foxracer62
  • Foxracer62
yes
daisydukeee
  • daisydukeee
Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credit. \[x ^{2} + 2x + y ^{2} + 4y = 20\]
daisydukeee
  • daisydukeee
This is what I have so far x² + 2x + y² + 4y = 20 (x² + 2x) + (y² + 4y) = 20 (x² + 2x+1) + (y² + 4y+4) = 20 + (1 + 4) (x² + 2x+1) + (y² + 4y+4) = 25

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Foxracer62
  • Foxracer62
k give me a sec to solve
daisydukeee
  • daisydukeee
I have been using this for the steps. I'm on step 4, but I can't quite seem to figure out how to "factor each quadratic".
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Foxracer62
  • Foxracer62
ok so take the question and type it into mathway (mathway.com) it will give you the answer and the steps
daisydukeee
  • daisydukeee
Okay, I will try that. Thanks.
Foxracer62
  • Foxracer62
Medal?
anonymous
  • anonymous
you can really go right to the answer without all that rigamarole
anonymous
  • anonymous
\[x ^{2} + 2x + y ^{2} + 4y = 20\] half of 2 is 1, \(6^2=1\) half of 4 is 2, \(2^2=4\) go right from there to \[(x+1)^2+(y+2)^2=20+1+4\]
anonymous
  • anonymous
oops i meant "\(1^2=1\)"
daisydukeee
  • daisydukeee
Oh okay, so the center would be (1,2) and the radius would be 5?
anonymous
  • anonymous
no
anonymous
  • anonymous
the radius is 5, that is correct
anonymous
  • anonymous
center is \((-1,-2)\)
daisydukeee
  • daisydukeee
Ah gotcha. I get it. Thank you!
anonymous
  • anonymous
yw

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