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anonymous
 one year ago
Use the functions a(x) = 3x + 10 and b(x) = 2x − 8 to complete the function operations listed below.
Part A: Find (a + b)(x). Show your work. (3 points)
Part B: Find (a ⋅ b)(x). Show your work. (3 points)
Part C: Find a[b(x)]. Show your work. (4 points)
anonymous
 one year ago
Use the functions a(x) = 3x + 10 and b(x) = 2x − 8 to complete the function operations listed below. Part A: Find (a + b)(x). Show your work. (3 points) Part B: Find (a ⋅ b)(x). Show your work. (3 points) Part C: Find a[b(x)]. Show your work. (4 points)

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zepdrix
 one year ago
Best ResponseYou've already chosen the best response.3\[\large\rm \color{royalblue}{a(x) = 3x + 10},\qquad \color{orangered}{b(x) = 2x − 8}\] \[\large\rm (a+b)(x)=\color{royalblue}{a(x)}+\color{orangered}{b(x)}\]\[\large\rm (a+b)(x)=\color{royalblue}{3x+10}+\color{orangered}{2x8}\]Combine liketerms! :)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.3Yay good job! That takes care of part A.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.3For part B, you'll want to put some brackets around your a(x) and b(x) so the multiplication works out properly.\[\large\rm (a\cdot b)(x)=(\color{royalblue}{a(x)})\cdot(\color{orangered}{b(x)})\]\[\large\rm (a\cdot b)(x)=(\color{royalblue}{3x+10})\cdot(\color{orangered}{2x8})\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(3x+10)(2x+−8) =(3x)(2x)+(3x)(−8)+(10)(2x)+(10)(−8) =6x2−24x+20x−80 =6x2−4x−80

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.3How bout part C, the composition. Having any trouble with that one?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes thats actually the one i am confused on >_<

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.3\[\large\rm a(\color{#DD4747}{x}) = 3\color{#DD4747}{x} + 10\]We're replacing all of the x's in our function a(x) with another function b(x).\[\large\rm a(\color{#DD4747}{b(x)}) = 3\color{#DD4747}{b(x)} + 10\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.3But again, since we have some multiplication going on, let's place brackets around the b(x) before we plug it in.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.3\[\large\rm a(\color{#DD4747}{b(x)}) = 3(\color{#DD4747}{b(x)}) + 10\]\[\large\rm a(\color{#DD4747}{b(x)}) = 3(\color{#DD4747}{2x8}) + 10\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0=(3)(2x)+(3)(−8)+10 =6x+−24+10 =6x+−24+10 =(6x)+(−24+10) =6x+−14

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i need help on part A!!!

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.3Then scroll up and read silly! :D

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.3Recall that addition is commutative, meaning we can move things around. So \(\large\rm 3x+10+2x8\) is the same as \(\large\rm 3x+2x+108\) Combine your x's. You have 3 of them, and 2 more of them. 3 apples + 2 apples = ?
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