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marihelenh

  • one year ago

What is the magnitude of the displacement of a car that travels half a lap along a circle of radius of 150m?

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  1. marihelenh
    • one year ago
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    @Shalante Can you help me please?

  2. marihelenh
    • one year ago
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    @triciaal

  3. triciaal
    • one year ago
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    |dw:1440969538478:dw|

  4. triciaal
    • one year ago
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    displacement is equivalent to distance one lap is the perimeter of the circle= circumference = 2 * pi* r 1/2 lap = 1/2 * 2 * pi* r and r is the radius 150

  5. marihelenh
    • one year ago
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    Ok, I see how that is, but that is describing the distance. My book says displacement is the straight-line distance between two points. Would that mean I double the radius because it would be equal to the diameter?

  6. triciaal
    • one year ago
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    magnitude strength

  7. marihelenh
    • one year ago
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    What does that mean?

  8. triciaal
    • one year ago
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    |dw:1440970129330:dw|

  9. triciaal
    • one year ago
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    no

  10. triciaal
    • one year ago
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    @zepdrix thanks

  11. triciaal
    • one year ago
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    @amistre64 @phi

  12. triciaal
    • one year ago
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    @hero do you mind helping?

  13. amistre64
    • one year ago
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    displacement is how far you are from the place you started. not how far you have traveled to get there.

  14. marihelenh
    • one year ago
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    So would I just double the radius because the car went half the circle?

  15. amistre64
    • one year ago
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    yes

  16. marihelenh
    • one year ago
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    So, to be clear, the displacement would be 300m?

  17. amistre64
    • one year ago
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    thats the way it looks to me yes, the car is 2 radiuses from where it started

  18. marihelenh
    • one year ago
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    Thank you! Do you know what it means by the magnitude of displacement?

  19. amistre64
    • one year ago
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    magnitude is the measure of the displacement

  20. amistre64
    • one year ago
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    as opposed to the direction of the displacment

  21. marihelenh
    • one year ago
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    Oooohhh. That makes a lot more sense now. Thanks!

  22. amistre64
    • one year ago
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    consider displacement as a vector, it has both length and direction ...

  23. triciaal
    • one year ago
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    stand corrected does this mean we are not dealing with vectors?

  24. amistre64
    • one year ago
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    we are dealing with a vector, but just the magnitude of it

  25. amistre64
    • one year ago
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    |dw:1440971991073:dw|

  26. marihelenh
    • one year ago
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    That makes sense to me now. I have some more questions. Could you help me with them? I am taking an advanced physics class and my teacher never explained any of this, she just assigned the homework, so I am not always sure if I am on the right track.

  27. triciaal
    • one year ago
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    @amistre64 thank you for your support

  28. amistre64
    • one year ago
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    physics isnt my strong point, i just know some basic stuff. ask and we can see if i can help ... if not there are others

  29. marihelenh
    • one year ago
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    Ok, great. I will start a new question.

  30. amistre64
    • one year ago
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    k, and triciaal is a smart cookie ... her insight is good for the most part ;)

  31. triciaal
    • one year ago
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    did advanced physics, chemistry and math but that was a long, long, long time ago

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