anonymous
  • anonymous
I'm working with limits and the ones with trig always stump me..can someone please help me with this problem?
Calculus1
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
helps out alot if you post the problem details
anonymous
  • anonymous
I attached a picture, can you get to it?
anonymous
  • anonymous
If not, here is the problem: Find the limit lim as x approaches 0 of sin^2x/x

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
@amistre64
amistre64
  • amistre64
there is no picture attached on my end to see ...
amistre64
  • amistre64
sin(x)/x * sin(x) the limit of a product is the product of the limits i think is rule of thumb
amistre64
  • amistre64
lhopital also works but i dont think your into that yet
amistre64
  • amistre64
sin^2 to 2 sin cos
anonymous
  • anonymous
So my limit would just be sinx? @amistre64

Looking for something else?

Not the answer you are looking for? Search for more explanations.