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anonymous
 one year ago
cube root (8xh^5xs^3)/cube root (h^9xs^9). Please help!
anonymous
 one year ago
cube root (8xh^5xs^3)/cube root (h^9xs^9). Please help!

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phi
 one year ago
Best ResponseYou've already chosen the best response.1do the x's mean variable x or times?

phi
 one year ago
Best ResponseYou've already chosen the best response.1ok. people don't use x in algebra to mean times. too confusing. (8xh^5xs^3)/cube root (h^9xs^9) \[ \frac{ \sqrt[3]{8h^{5}s^{3}}}{ \sqrt[3]{h^{9}s^{9}}} \] is this it?

phi
 one year ago
Best ResponseYou've already chosen the best response.1I would rewrite that using exponent 1/3 instead of cube root sign It means the same thing, but easier to manipulate \[\left( \frac{ 8h^{5}s^{3}}{h^{9}s^{9}}\right)^\frac{1}{3} \]

phi
 one year ago
Best ResponseYou've already chosen the best response.1do you know how to figure out \[ \frac{h^{5}}{h^{9}}\]?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you make the 9 positive by bring it up to the numerator?

phi
 one year ago
Best ResponseYou've already chosen the best response.1you could. 1/h^9 means the same as h^9 there are "short cut rules" when multiplying or dividing the same base with different exponents.

phi
 one year ago
Best ResponseYou've already chosen the best response.1the simplest rule is an extension of this idea: \[ h \cdot h = h^2\] if we put in the exponents to make it more obvious \[ h^1 \cdot h^1 = h^{1+1}= h^2\] we add the exponents. another example: h*h*h * h*h using the "short version" that is obviously h^5 it is also h^3 * h^2 and we see adding 3+2 gives us the right answer: h^5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay, so the question wants me to put it into kh^rs^t. I got 2h^4/3s^2

phi
 one year ago
Best ResponseYou've already chosen the best response.1on the other hand \[ \frac{h\cdot h}{h} = h \] and that is \[ \frac{h^2}{h^1} = h^{21}= h^1= h \] we subtract top exponent minus bottom exponent

phi
 one year ago
Best ResponseYou've already chosen the best response.1using the subtract rule h^5/ h^9 = h^(5  (9)) 5  9 is 5+9 = +4 h^4 is the simplified version

phi
 one year ago
Best ResponseYou've already chosen the best response.1now do the s's s^3 / s^9 the new exponent will be 3  9 = 12 so s^12 and though not obvious, 8= 2^3 we have so far \[ \left(2^3 h^4 s^{12}\right)^\frac{1}{3} \]

phi
 one year ago
Best ResponseYou've already chosen the best response.1and we can take the cube root of each term inside notice the s^4 is up top. (if we put it down below it will become 1/s^4 ) \[ 2 h^\frac{4}{3} s^{4} \]

phi
 one year ago
Best ResponseYou've already chosen the best response.1I think no parens confused me I would write it as 2 h^(4/3) s^(4)

phi
 one year ago
Best ResponseYou've already chosen the best response.1because they want it in the form k h^r s^t

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh I got the question right! thank you!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0they wanted me to keep the negative exponent
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