anonymous
  • anonymous
An urn contains 10 red balls, 10 green balls, and 5 white balls. 5 balls are selected. In how many ways can 5 balls be drawn if at least 3 are green?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Someone please help!!!!
Loser66
  • Loser66
@ganeshie8 I love the way you break the green as an independent variable. Please, do it again. :)
anonymous
  • anonymous
can someone just help me please?

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More answers

mathmath333
  • mathmath333
@JosephDeng what is the answer given in ur book
mathmath333
  • mathmath333
i think it is \(\dbinom{15}{2}+\dbinom{15}{1}+1=121\)
mathmate
  • mathmate
@JosephDeng Hint: We just need to know that there are 10 green and 15 non-green. The number of combinations of pulling 3 green (10 choose 3) and 2 non green (15 choose 2) =\(\dbinom{10}{3}\dbinom{15}{2}=12600\) Total number of combinations (25 choose 5) = \(\dbinom{25}{5}=53130\) Can you take it from here to find P(at least 3 green)?
anonymous
  • anonymous
the answer is 16002
mathmate
  • mathmate
Yes, the answer is correct. \(\dbinom{10}{3}\dbinom{15}{2}+\dbinom{10}{4}\dbinom{15}{1}+\dbinom{10}{5}\dbinom{15}{0}=16002\)

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