A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
An urn contains 10 red balls, 10 green balls, and 5 white balls. 5 balls are selected. In how many ways can 5 balls be drawn if at least 3 are green?
anonymous
 one year ago
An urn contains 10 red balls, 10 green balls, and 5 white balls. 5 balls are selected. In how many ways can 5 balls be drawn if at least 3 are green?

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Someone please help!!!!

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 I love the way you break the green as an independent variable. Please, do it again. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can someone just help me please?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0@JosephDeng what is the answer given in ur book

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0i think it is \(\dbinom{15}{2}+\dbinom{15}{1}+1=121\)

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1@JosephDeng Hint: We just need to know that there are 10 green and 15 nongreen. The number of combinations of pulling 3 green (10 choose 3) and 2 non green (15 choose 2) =\(\dbinom{10}{3}\dbinom{15}{2}=12600\) Total number of combinations (25 choose 5) = \(\dbinom{25}{5}=53130\) Can you take it from here to find P(at least 3 green)?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Yes, the answer is correct. \(\dbinom{10}{3}\dbinom{15}{2}+\dbinom{10}{4}\dbinom{15}{1}+\dbinom{10}{5}\dbinom{15}{0}=16002\)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.