Which ordered pairs are solutions to the inequality y – 4x ≤ –6?
Choose all answers that are correct.
A. (–2, –14)
B. (–1, –9)
C. (0, –5)
D. (1, 3)
E. (3, 5)

- freemap

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- freemap

@radar

- freemap

please help me

- phi

what is the first (-2,-14) ?

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## More answers

- freemap

like plugin in -2 for x

- phi

It is not labeled as a choice? or is it supposed to be choice A ?

- freemap

yes,

- freemap

No I mean sorry

- phi

can you edit the question? otherwise it will be confusing

- freemap

ok

- freemap

Which ordered pairs are solutions to the inequality y – 4x ≤ –6?
Choose all answers that are correct.
A.(–2, –14)
B.(–1, –9)
C.(0, –5)
D.(3, 5)
E.(1,3)
There all answer choices, pick all that are correct

- phi

y-4x are "instructions" that says
multiply the first number ( the x number in a pair) by -4
then add it to the 2nd number (the y number in a pair)
can you do that for the pair (-2,-14) ?

- freemap

ok, you don't have use answer choices. May i have an example

- phi

for (-2,-14)
multiply the first number by -4: -2*-4
then add the 2nd number: -14
can you do that ?

- freemap

ok

- freemap

16--14=30

- phi

first do -2*-4

- freemap

8

- phi

now add -14

- freemap

-6

- phi

yes. now we have
\[ y - 4x \le -6 \\ -6 \le -6\]
the little _ under the \( \lt\) means equal.
is -6 = -6 ?
yes.
so choice A works.

- freemap

ok, now do the same thing for all of them

- phi

now try
(–1, –9)
in
-4x+y (this means the same as y + -4x or y-4x)
and you do
-4* -1
add -9

- freemap

4+9=13

- phi

the 2nd number in (-1,-9) is not +9. it is -9

- freemap

5

- phi

4+ -9 = what ?

- freemap

-5

- phi

when you add numbers with different signs, subtract them (ignoring the sign)
and make the answer the same sign as the "bigger" number.
yes we get -5

- phi

now
\[ -5 \le -6\]
it is clearly not equal.
notice the "big" end of the \( \le\) is next to -6. that means we want -6 to be bigger than the other side
is -6 bigger than -5 ?

- freemap

no

- phi

ok, -5 is bigger than -6 and we want numbers smaller than -6
so cross off choice B.
so far , only A works.

- freemap

ok

- phi

C. (0, –5)
-4 x + y
do -4 * 0
then add -5

- freemap

-5

- phi

and we just did \( -5 \le -6\). Not true. cross off choice C

- freemap

ok

- phi

can you try
D. (3, 5)
and show your steps.

- freemap

ok

- freemap

D. (3,5)
-4x + y
-4 * 3=-12
add 5
=-7

- phi

ok, and is \(-7 \le -6\) true or false?

- freemap

yes

- freemap

true

- phi

ok, so choice A and choice D
one more to go
E. (3, 5)

- freemap

I thought we just did 3,5

- phi

wait, E is (1,3)

- freemap

E. (1,3)
-4x+y
-4*1=-4
add 3, -4+3=-1
-1 Is bigger than -6 so the equation is false

- phi

yes. now double check your question, that choice D is (3,5) and E is (1,3)
up top you have it the other way round.

- freemap

It is, Thanks so much, You've been a great help. Could you check another one of my answer. I'll post again

- phi

ok

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