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amy0799

  • one year ago

Determine the point at which the graph of the function below has a horizontal tangent line. y = 8x^2 + 8 x= ?

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  1. Loser66
    • one year ago
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    take derivative of y, what do you get?

  2. amy0799
    • one year ago
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    @Loser66 16x

  3. Loser66
    • one year ago
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    when it is =0?

  4. amy0799
    • one year ago
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    I don't know...

  5. Loser66
    • one year ago
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    |dw:1440972769588:dw|

  6. amy0799
    • one year ago
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    0

  7. Loser66
    • one year ago
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    write down both sides, please.

  8. amy0799
    • one year ago
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    what do you mean both sides?

  9. Loser66
    • one year ago
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    |dw:1440972865500:dw|

  10. Loser66
    • one year ago
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    Got it?

  11. amy0799
    • one year ago
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    so that's the answer?

  12. Loser66
    • one year ago
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    yup

  13. amy0799
    • one year ago
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    thank you! can you help me with another?

  14. amy0799
    • one year ago
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    @Loser66

  15. Loser66
    • one year ago
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    not sure. have to see it first

  16. amy0799
    • one year ago
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    Find k such that the line y = 2x + 18 is tangent to the graph of the function below. \[y=k \sqrt{x}\] k=?

  17. Loser66
    • one year ago
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    take derivative of the curve y = ksqrt x, what do you get?

  18. amy0799
    • one year ago
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    1/2k^-1/2

  19. amy0799
    • one year ago
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    @Loser66

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spraguer (Moderator)
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