Determine the point at which the graph of the function below has a horizontal tangent line. y = 8x^2 + 8 x= ?

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Determine the point at which the graph of the function below has a horizontal tangent line. y = 8x^2 + 8 x= ?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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take derivative of y, what do you get?
when it is =0?

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Other answers:

I don't know...
|dw:1440972769588:dw|
0
write down both sides, please.
what do you mean both sides?
|dw:1440972865500:dw|
Got it?
so that's the answer?
yup
thank you! can you help me with another?
not sure. have to see it first
Find k such that the line y = 2x + 18 is tangent to the graph of the function below. \[y=k \sqrt{x}\] k=?
take derivative of the curve y = ksqrt x, what do you get?
1/2k^-1/2

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