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Mutie
 one year ago
** I NEED HELP **
( Will medal and fan like always )

Diagram:
http://prntscr.com/8as6gf

Jocelyn wants to adopt one star for her mother and one star for her father. She has narrowed her choices down to four stars that are located on a straight line from the earth.
Jocelyn wants to adopt the two stars that are closest to each other.
1. Which two stars should she adopt?
2. What is the distance between the stars? (Hint: Make a diagram and align the stars in order from closest to farthest from the earth.)
3. Show or explain your work.

I don't really understand how t
Mutie
 one year ago
** I NEED HELP ** ( Will medal and fan like always )  Diagram: http://prntscr.com/8as6gf  Jocelyn wants to adopt one star for her mother and one star for her father. She has narrowed her choices down to four stars that are located on a straight line from the earth. Jocelyn wants to adopt the two stars that are closest to each other. 1. Which two stars should she adopt? 2. What is the distance between the stars? (Hint: Make a diagram and align the stars in order from closest to farthest from the earth.) 3. Show or explain your work.  I don't really understand how t

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Mutie
 one year ago
Best ResponseYou've already chosen the best response.0I need to show my work on every problem at least, I don't really understand what to do though.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2how do we know the distance between 2 things?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2i dont know how your material does it, but id at least get them all speaking the same term ... the lowest exponent

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2.176 x 10^(14+4) > 1760 x 10^4 22.13 x 10^(14+2) > 2213 x 10^4 31.42 x 10^(14+0) > 31.42 x 10^4 125.5 x 10^(14+1) > 1255 x 10^4 now its simpler to compare the distances

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2bah, all those are 10^(14) not 10^(4) .... minor typo, but the rest is correct

Mutie
 one year ago
Best ResponseYou've already chosen the best response.0So with that.. do I work them out? Sorry if I'm incorrect, I'm still a bit confused.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2ideally yes, or logically we can conclude that 31 is not going to be closer to any of the others by default we can then average the low and high that remains to see where the middle falls .... (2213+1255)/2 = 1734 the middle is on the high side of 1734 so we have our closest starts

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2part 2 is just listing the starts by order of distance, and 3 is explaining your work

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2but the thing is, my thought process is not going to conform to the method your material expects of you ... so this is just something that would work from my head

Mutie
 one year ago
Best ResponseYou've already chosen the best response.0So our closest stars would be... 1760 x 10^4 and 1255 x 10^4 ? ( AKA, Star A and Star D?)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2work your process AB AC AD BC BD CD

amistre64
 one year ago
Best ResponseYou've already chosen the best response.222 and 17 are the closest to each other

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2dw:1440978143962:dw

Mutie
 one year ago
Best ResponseYou've already chosen the best response.0I see, but for question one (Which two stars should she adopt?) the answer would be Star A and D? Or am I answering that question wrong?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2she want the 2 stars that are the closest to each other ... i see that as A and B

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2when we take the midpoint of 12 and 22, we get 1734 if 1734 is the middle point, then 1760 is closer to the high side then the low side

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2the key to me is to get them speaking all in the same 10^(14) formats so that all we do is compare the multipliers

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2for a general proof, spose we have 2 numbers a x 10^n and b x 10^n subtract them a x 10^n  b x 10^n factor out the common 10^n 10^n (a  b) the difference is determined by a and b, and not the base 10 stuff

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2if we let them all speak in terms of 10^(14) then the rest is just working with the multipler parts and we can ignore the 10^(14)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2since 31 is clearly not anywhere near the other 3, its immaterial to us by taking the midpoint of the remaining extremes, we can judge were to place the inbetween value ... (2213 + 1255)/2 = 1734 so we know that inbetween value will fall to one side or the other, and be closer to that side 1255 ... 1734 .... 2213 ^ 1760 by default, the 17 and 22 are closest to each other

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2how you express this the way your material wants you to .... i got no clue tho

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2you write it up i terms you comprehend and ill review it for you
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