anonymous
  • anonymous
Solve the triangle. A = 52°, b = 14, c = 6
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Zale101
  • Zale101
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Zale101
  • Zale101
What law are you going to use?
Zale101
  • Zale101
Law of sine will pretty much get you the answer. Any ideas of how to use the law of sine?

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anonymous
  • anonymous
sin?
Zale101
  • Zale101
Yes
anonymous
  • anonymous
will A= 14.9 C=24.2 B=103.8 ?
Zale101
  • Zale101
The Law of Sine or the Sine rule says: \(\Large \frac{Sin(A)}{a}=\frac{Sine(B)}{b}=\frac{Sin(C)}{c}\)
Zale101
  • Zale101
How did you get that answer @Abbs__ ?
anonymous
  • anonymous
I just plugged it in
Zale101
  • Zale101
Can you show me your work?
anonymous
  • anonymous
idk how to do that, is it wrong ?
Zale101
  • Zale101
I'm not going to give out the answer unless you participate in your question and start showing some work.
anonymous
  • anonymous
okay I obviously did the work, how do I take a picture of it and send it.
jim_thompson5910
  • jim_thompson5910
@Zale101 the law of sines won't work here yet. We need to know either B or C. To start off, use the law of cosines to solve for 'a'. After that, the law of sines can be used.
Zale101
  • Zale101
Thanks @jim_thompson5910 !!!
jim_thompson5910
  • jim_thompson5910
sure thing
anonymous
  • anonymous
I literally did that tho
Zale101
  • Zale101
@Abbs__ Jim is right, you start off by using the law of cosines, to know B or C because apparently you can't go straight ahead and do the law of sines because it wont work. Your question only shows A, then b and c. We can't have Sin(A)/a because we only know A and a is not giving, same goes for B and C. There's missing parts that's why we can't use the laws of sine. Thanks again, jim Step 1: Laws of Cosine Step 2: Laws of sine
Zale101
  • Zale101
@Abbs__ can you then show us what you did?
anonymous
  • anonymous
I asked how to do that twice
jim_thompson5910
  • jim_thompson5910
Law of Cosines a^2 = b^2 + c^2 - 2*b*c*cos(A) a^2 = 14^2 + 6^2 - 2*14*6*cos(52) ... make the proper substitutions now isolate 'a'

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