## anonymous one year ago Solve the triangle. A = 52°, b = 14, c = 6

1. Zale101

|dw:1440977299136:dw|

2. Zale101

What law are you going to use?

3. Zale101

Law of sine will pretty much get you the answer. Any ideas of how to use the law of sine?

4. anonymous

sin?

5. Zale101

Yes

6. anonymous

will A= 14.9 C=24.2 B=103.8 ?

7. Zale101

The Law of Sine or the Sine rule says: $$\Large \frac{Sin(A)}{a}=\frac{Sine(B)}{b}=\frac{Sin(C)}{c}$$

8. Zale101

How did you get that answer @Abbs__ ?

9. anonymous

I just plugged it in

10. Zale101

Can you show me your work?

11. anonymous

idk how to do that, is it wrong ?

12. Zale101

I'm not going to give out the answer unless you participate in your question and start showing some work.

13. anonymous

okay I obviously did the work, how do I take a picture of it and send it.

14. jim_thompson5910

@Zale101 the law of sines won't work here yet. We need to know either B or C. To start off, use the law of cosines to solve for 'a'. After that, the law of sines can be used.

15. Zale101

Thanks @jim_thompson5910 !!!

16. jim_thompson5910

sure thing

17. anonymous

I literally did that tho

18. Zale101

@Abbs__ Jim is right, you start off by using the law of cosines, to know B or C because apparently you can't go straight ahead and do the law of sines because it wont work. Your question only shows A, then b and c. We can't have Sin(A)/a because we only know A and a is not giving, same goes for B and C. There's missing parts that's why we can't use the laws of sine. Thanks again, jim Step 1: Laws of Cosine Step 2: Laws of sine

19. Zale101

@Abbs__ can you then show us what you did?

20. anonymous

I asked how to do that twice

21. jim_thompson5910

Law of Cosines a^2 = b^2 + c^2 - 2*b*c*cos(A) a^2 = 14^2 + 6^2 - 2*14*6*cos(52) ... make the proper substitutions now isolate 'a'