Solve the triangle. A = 52°, b = 14, c = 6

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Solve the triangle. A = 52°, b = 14, c = 6

Mathematics
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What law are you going to use?
Law of sine will pretty much get you the answer. Any ideas of how to use the law of sine?

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sin?
Yes
will A= 14.9 C=24.2 B=103.8 ?
The Law of Sine or the Sine rule says: \(\Large \frac{Sin(A)}{a}=\frac{Sine(B)}{b}=\frac{Sin(C)}{c}\)
How did you get that answer @Abbs__ ?
I just plugged it in
Can you show me your work?
idk how to do that, is it wrong ?
I'm not going to give out the answer unless you participate in your question and start showing some work.
okay I obviously did the work, how do I take a picture of it and send it.
@Zale101 the law of sines won't work here yet. We need to know either B or C. To start off, use the law of cosines to solve for 'a'. After that, the law of sines can be used.
Thanks @jim_thompson5910 !!!
sure thing
I literally did that tho
@Abbs__ Jim is right, you start off by using the law of cosines, to know B or C because apparently you can't go straight ahead and do the law of sines because it wont work. Your question only shows A, then b and c. We can't have Sin(A)/a because we only know A and a is not giving, same goes for B and C. There's missing parts that's why we can't use the laws of sine. Thanks again, jim Step 1: Laws of Cosine Step 2: Laws of sine
@Abbs__ can you then show us what you did?
I asked how to do that twice
Law of Cosines a^2 = b^2 + c^2 - 2*b*c*cos(A) a^2 = 14^2 + 6^2 - 2*14*6*cos(52) ... make the proper substitutions now isolate 'a'

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