x^-2+x^-4=
I got x^1/2+x^1/4 but i dont remember the rules well for exponents

- anonymous

x^-2+x^-4=
I got x^1/2+x^1/4 but i dont remember the rules well for exponents

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- jamiebookeater

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- freckles

x^(-2) doesn't mean x^(1/2)
though you can write x^(-2) as 1/x^2

- freckles

and same for the x^(-4) this is not x^(1/4)

- anonymous

ohhh okay so do i multiply the exponents?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- Jhannybean

\[x^{-2} -x^{-4}\] You're just looking to factor out this function?

- anonymous

well for the exponents, it says to put it in A/B

- Jhannybean

Oh okay, so as @freckles mentioned :)

- Jhannybean

Recall that \(x^{-\#} \iff \dfrac{1}{x^{\#}}\)
Therefore we can write our function over 1 to make the exponents of the variables positive :)
and i made a typo, my function should have read \(x^{-2} + x^{-4}\)*

- anonymous

i got that now! so do we multiply the exponents to get 1/x^8?

- anonymous

i completely forgot the rules

- anonymous

then how?

- Jhannybean

All we can do now, is factor out the denominator.

- freckles

\[x^{-2}+x^{-4}=\frac{1}{x^2}+\frac{1}{x^4}\]
you can combine the fractions by finding a common denominator

- Jhannybean

D'oh!

- Jhannybean

I made a really big error. My mistake was in putting the function as a whole in the denominator. In order to turn each variable positive, you must treat each variable as a separate function.

- Jhannybean

From what @freckles wrote, just find the greatest common denominator between \(x^2\) and \(x^4\).

- anonymous

?

- anonymous

common denominator is x^4?

- freckles

that is right
\[x^{-2}+x^{-4} \\ \frac{1}{x^2}+\frac{1}{x^4} \\ \frac{1(x^2)}{x^2(x^2)}+\frac{1}{x^4}\]
now you have the same denominator
combine the fractions

- anonymous

so itll be x^2/x^4
do i reduce?

- freckles

you will have
\[\frac{x^2+1}{x^4}\]

- anonymous

wouldnt that equal to x+1/x^2

- freckles

no just (x^2+1)/x^4
can't be reduced because you don't have all terms with factor x^2

- anonymous

than would A/B be 2/4? cause the question asked put the exponents as A/B

- freckles

what?

- freckles

are you saying we are suppose to write in x^(A/B) form?

- anonymous

yes

- freckles

\[x^{-2}+x^{-4}=x^{\frac{-2}{1}}+x^{\frac{-4}{1}}\]
there is both terms written in x^(A/B) form

- anonymous

oh okay thats easier to understand

- anonymous

then would it be -6

- freckles

I don't get your question
can you post your whole question

- anonymous

simplofy the rational expression in the form of A/B. x^-2+x^-4

- freckles

oh in the form A/B
well we did that
\[\frac{x^2+1}{x^4} \\ \text{ we have } A=x^2+1 \text{ and } B=x^4\]

- anonymous

oh my god thank you!

- freckles

np

Looking for something else?

Not the answer you are looking for? Search for more explanations.