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x^(-2) doesn't mean x^(1/2)
though you can write x^(-2) as 1/x^2

and same for the x^(-4) this is not x^(1/4)

ohhh okay so do i multiply the exponents?

\[x^{-2} -x^{-4}\] You're just looking to factor out this function?

well for the exponents, it says to put it in A/B

Oh okay, so as @freckles mentioned :)

i got that now! so do we multiply the exponents to get 1/x^8?

i completely forgot the rules

then how?

All we can do now, is factor out the denominator.

D'oh!

From what @freckles wrote, just find the greatest common denominator between \(x^2\) and \(x^4\).

common denominator is x^4?

so itll be x^2/x^4
do i reduce?

you will have
\[\frac{x^2+1}{x^4}\]

wouldnt that equal to x+1/x^2

no just (x^2+1)/x^4
can't be reduced because you don't have all terms with factor x^2

than would A/B be 2/4? cause the question asked put the exponents as A/B

what?

are you saying we are suppose to write in x^(A/B) form?

yes

\[x^{-2}+x^{-4}=x^{\frac{-2}{1}}+x^{\frac{-4}{1}}\]
there is both terms written in x^(A/B) form

oh okay thats easier to understand

then would it be -6

I don't get your question
can you post your whole question

simplofy the rational expression in the form of A/B. x^-2+x^-4

oh my god thank you!

np