El_Arrow
  • El_Arrow
Need help please!
Mathematics
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions.

El_Arrow
  • El_Arrow
Need help please!
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

El_Arrow
  • El_Arrow
find the volume of the solid formed by revolving the region bounded by the graph of f(x) = x^2 and g(x) = 12-x to the right of x=1 about the y-axis
El_Arrow
  • El_Arrow
first thing i did was set f(x) and g(x) equal to one another and i got -4 and 3
El_Arrow
  • El_Arrow
|dw:1440982705148:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

freckles
  • freckles
\[x^2=12-x \\ x^2+x-12=0 \\ (x+4)(x-3)=0 \\ x=-4 \text{ or } x=3 \] (-4)^2=16 (3)^2=9 |dw:1440982735696:dw|
freckles
  • freckles
|dw:1440982829162:dw| we are looking at this region (the shaded region) right?
El_Arrow
  • El_Arrow
yes
El_Arrow
  • El_Arrow
so it would be the integral from 1 to 3 @freckles ?
freckles
  • freckles
yea
freckles
  • freckles
so it looks like you were trying to use shells method
El_Arrow
  • El_Arrow
yes thats correct
freckles
  • freckles
|dw:1440983126638:dw|
El_Arrow
  • El_Arrow
so something like this |dw:1440983268893:dw|
freckles
  • freckles
yes. |dw:1440983363623:dw|
El_Arrow
  • El_Arrow
but why do you have the square root over the x why not x^2
freckles
  • freckles
lol
freckles
  • freckles
I forgot what function we were using
freckles
  • freckles
sqrt(x) is suppose to be x^2
El_Arrow
  • El_Arrow
oh okay lol
freckles
  • freckles
i'm sorry i do idiot things sometimes
El_Arrow
  • El_Arrow
its okay
freckles
  • freckles
|dw:1440983615720:dw|
El_Arrow
  • El_Arrow
the answer is 116pi/3 but i got 16pi?
freckles
  • freckles
hmm so the radius should have been just x
El_Arrow
  • El_Arrow
i think so let me see if it works
freckles
  • freckles
|dw:1440983787477:dw|
freckles
  • freckles
|dw:1440983907300:dw| so you were right to begin with you just needed 1 to 3 instead of 0 to 1
El_Arrow
  • El_Arrow
yeah i got right now thanks alot
freckles
  • freckles
it does make sense I think if I had looked at that whole thing from 0 to 3 and subtract out the part that is 0 to 1 we would have seen it better \[\int\limits_0^3 2\pi(x)(12-x-x^2) dx-\int\limits_0^1 2\pi(x)(12-x-x^2)dx \\ =\int\limits_1^3 2 \pi (x) (12-x-x^2) dx\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.