The square root of 5 +the square root of 80 = the square root of 5 + square root of 16 times 5 = the square root + 4 and the square root of 5 = 5 and the square root of 5. I am willing to offer medals if who ever helps me is willing to help with a few other problems tomorrow and also explain the process. I will give you medals for each individual problem if you become a fan and help me out with these Radicals and Complex Numbers. Thanks!!!

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The square root of 5 +the square root of 80 = the square root of 5 + square root of 16 times 5 = the square root + 4 and the square root of 5 = 5 and the square root of 5. I am willing to offer medals if who ever helps me is willing to help with a few other problems tomorrow and also explain the process. I will give you medals for each individual problem if you become a fan and help me out with these Radicals and Complex Numbers. Thanks!!!

Mathematics
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√(5) + √(80) = √(5) + √(16*5) = √(5) + __ √(5) = __ Here is a visual of my problem
You use the rule \[\Large \sqrt{x*y} = \sqrt{x}*\sqrt{y}\]
so, \[\Large \sqrt{16*5} = \sqrt{16}*\sqrt{5}\] \[\Large \sqrt{16*5} = ??\]

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I guess? Im super confused I haven't worked on a problem like this in a while. If your familiar with my math lab then that's where I've gotten this problem from.
if you can explain the process of how you get the answer too then that will be great as well.
what is the square root of 16 equal to?
the square root of 4 then the square root of 2
the square root of 16 is 4 once you take the square root, the square root symbol goes away
\[\Large \Large \sqrt{16*5} = \sqrt{16}*\sqrt{5}\] \[\Large \Large \sqrt{16*5} = 4\sqrt{5}\]
THe answer is supposed to be 5 on the square root of 5 im just confused on why that is the answer and how they are getting the answer so that I can other questions like one
5√(5)
so do you see how \[\Large \Large \sqrt{16*5} = 4\sqrt{5}\] ??
you took the square root of each one individually right?
yes, the square root of 16 is 4 the square root of 5 is some decimal, so we leave that alone
so, \[\Large \sqrt{5}+\sqrt{16*5} = \sqrt{5}+4\sqrt{5}\]
yes bc its prime
there is a 1 in front of that first sqrt(5) term \[\Large \sqrt{5}+4\sqrt{5} = 1\sqrt{5}+4\sqrt{5}\]
the last step is to add the numbers outside the root 5 terms 1+4 = 5 think of it as 1x+4x = 5x where x is equal to sqrt(5)
oh okay i think i get it.
so you see how \[\Large 1\sqrt{5}+4\sqrt{5} = 5\sqrt{5}\] ?
yes I got the correct answer on another problem! thank you!! will you be on tomorrow?
yes I'll be online tomorrow
and I'm glad to be of help and that it's making more sense now
if so i will give you several other medals for each problem that i have
perfect!! okay tomorrow i will put on a few other problems for us to work with see ya tomorrow jim_thompson5910
ok sounds good, have a good day/night

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