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anonymous

  • one year ago

The square root of 5 +the square root of 80 = the square root of 5 + square root of 16 times 5 = the square root + 4 and the square root of 5 = 5 and the square root of 5. I am willing to offer medals if who ever helps me is willing to help with a few other problems tomorrow and also explain the process. I will give you medals for each individual problem if you become a fan and help me out with these Radicals and Complex Numbers. Thanks!!!

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  1. anonymous
    • one year ago
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    √(5) + √(80) = √(5) + √(16*5) = √(5) + __ √(5) = __ Here is a visual of my problem

  2. jim_thompson5910
    • one year ago
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    You use the rule \[\Large \sqrt{x*y} = \sqrt{x}*\sqrt{y}\]

  3. jim_thompson5910
    • one year ago
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    so, \[\Large \sqrt{16*5} = \sqrt{16}*\sqrt{5}\] \[\Large \sqrt{16*5} = ??\]

  4. anonymous
    • one year ago
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    I guess? Im super confused I haven't worked on a problem like this in a while. If your familiar with my math lab then that's where I've gotten this problem from.

  5. anonymous
    • one year ago
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    if you can explain the process of how you get the answer too then that will be great as well.

  6. jim_thompson5910
    • one year ago
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    what is the square root of 16 equal to?

  7. anonymous
    • one year ago
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    the square root of 4 then the square root of 2

  8. jim_thompson5910
    • one year ago
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    the square root of 16 is 4 once you take the square root, the square root symbol goes away

  9. jim_thompson5910
    • one year ago
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    \[\Large \Large \sqrt{16*5} = \sqrt{16}*\sqrt{5}\] \[\Large \Large \sqrt{16*5} = 4\sqrt{5}\]

  10. anonymous
    • one year ago
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    THe answer is supposed to be 5 on the square root of 5 im just confused on why that is the answer and how they are getting the answer so that I can other questions like one

  11. anonymous
    • one year ago
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    5√(5)

  12. jim_thompson5910
    • one year ago
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    so do you see how \[\Large \Large \sqrt{16*5} = 4\sqrt{5}\] ??

  13. anonymous
    • one year ago
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    you took the square root of each one individually right?

  14. jim_thompson5910
    • one year ago
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    yes, the square root of 16 is 4 the square root of 5 is some decimal, so we leave that alone

  15. jim_thompson5910
    • one year ago
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    so, \[\Large \sqrt{5}+\sqrt{16*5} = \sqrt{5}+4\sqrt{5}\]

  16. anonymous
    • one year ago
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    yes bc its prime

  17. jim_thompson5910
    • one year ago
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    there is a 1 in front of that first sqrt(5) term \[\Large \sqrt{5}+4\sqrt{5} = 1\sqrt{5}+4\sqrt{5}\]

  18. jim_thompson5910
    • one year ago
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    the last step is to add the numbers outside the root 5 terms 1+4 = 5 think of it as 1x+4x = 5x where x is equal to sqrt(5)

  19. anonymous
    • one year ago
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    oh okay i think i get it.

  20. jim_thompson5910
    • one year ago
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    so you see how \[\Large 1\sqrt{5}+4\sqrt{5} = 5\sqrt{5}\] ?

  21. anonymous
    • one year ago
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    yes I got the correct answer on another problem! thank you!! will you be on tomorrow?

  22. jim_thompson5910
    • one year ago
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    yes I'll be online tomorrow

  23. jim_thompson5910
    • one year ago
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    and I'm glad to be of help and that it's making more sense now

  24. anonymous
    • one year ago
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    if so i will give you several other medals for each problem that i have

  25. anonymous
    • one year ago
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    perfect!! okay tomorrow i will put on a few other problems for us to work with see ya tomorrow jim_thompson5910

  26. jim_thompson5910
    • one year ago
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    ok sounds good, have a good day/night

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