## anonymous one year ago The square root of 5 +the square root of 80 = the square root of 5 + square root of 16 times 5 = the square root + 4 and the square root of 5 = 5 and the square root of 5. I am willing to offer medals if who ever helps me is willing to help with a few other problems tomorrow and also explain the process. I will give you medals for each individual problem if you become a fan and help me out with these Radicals and Complex Numbers. Thanks!!!

1. anonymous

√(5) + √(80) = √(5) + √(16*5) = √(5) + __ √(5) = __ Here is a visual of my problem

2. jim_thompson5910

You use the rule $\Large \sqrt{x*y} = \sqrt{x}*\sqrt{y}$

3. jim_thompson5910

so, $\Large \sqrt{16*5} = \sqrt{16}*\sqrt{5}$ $\Large \sqrt{16*5} = ??$

4. anonymous

I guess? Im super confused I haven't worked on a problem like this in a while. If your familiar with my math lab then that's where I've gotten this problem from.

5. anonymous

if you can explain the process of how you get the answer too then that will be great as well.

6. jim_thompson5910

what is the square root of 16 equal to?

7. anonymous

the square root of 4 then the square root of 2

8. jim_thompson5910

the square root of 16 is 4 once you take the square root, the square root symbol goes away

9. jim_thompson5910

$\Large \Large \sqrt{16*5} = \sqrt{16}*\sqrt{5}$ $\Large \Large \sqrt{16*5} = 4\sqrt{5}$

10. anonymous

THe answer is supposed to be 5 on the square root of 5 im just confused on why that is the answer and how they are getting the answer so that I can other questions like one

11. anonymous

5√(5)

12. jim_thompson5910

so do you see how $\Large \Large \sqrt{16*5} = 4\sqrt{5}$ ??

13. anonymous

you took the square root of each one individually right?

14. jim_thompson5910

yes, the square root of 16 is 4 the square root of 5 is some decimal, so we leave that alone

15. jim_thompson5910

so, $\Large \sqrt{5}+\sqrt{16*5} = \sqrt{5}+4\sqrt{5}$

16. anonymous

yes bc its prime

17. jim_thompson5910

there is a 1 in front of that first sqrt(5) term $\Large \sqrt{5}+4\sqrt{5} = 1\sqrt{5}+4\sqrt{5}$

18. jim_thompson5910

the last step is to add the numbers outside the root 5 terms 1+4 = 5 think of it as 1x+4x = 5x where x is equal to sqrt(5)

19. anonymous

oh okay i think i get it.

20. jim_thompson5910

so you see how $\Large 1\sqrt{5}+4\sqrt{5} = 5\sqrt{5}$ ?

21. anonymous

yes I got the correct answer on another problem! thank you!! will you be on tomorrow?

22. jim_thompson5910

yes I'll be online tomorrow

23. jim_thompson5910

and I'm glad to be of help and that it's making more sense now

24. anonymous

if so i will give you several other medals for each problem that i have

25. anonymous

perfect!! okay tomorrow i will put on a few other problems for us to work with see ya tomorrow jim_thompson5910

26. jim_thompson5910

ok sounds good, have a good day/night