anonymous
  • anonymous
Identify the domain and range and sketch the graph of the function y=-sqrt-x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[y=\sqrt{-x}\]
anonymous
  • anonymous
\[y=-\sqrt{-x}\]
anonymous
  • anonymous
you can't take the square root of a negative number , solve \[-x\geq 0\] in one step to get the domain

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anonymous
  • anonymous
same domainfor \(y=-\sqrt{-x}\)makes no difference
anonymous
  • anonymous
as for the range, the square root is greater than or equal to zero, so minus the square root will be less than or equal to zero
anonymous
  • anonymous
Ok so the domian would be (-infinity, infinity)?
misty1212
  • misty1212
HI!!
misty1212
  • misty1212
and no
misty1212
  • misty1212
do you know how to solve \[-x\geq 0\] for \(x\)?
anonymous
  • anonymous
No
misty1212
  • misty1212
if not, that is fine, i will show you
anonymous
  • anonymous
Ok thanks
misty1212
  • misty1212
ok change the sign, and flip the inequality
anonymous
  • anonymous
Ok
misty1212
  • misty1212
the math teachers call it "multiply by \(-1\)" or sommat, but you just make it positive and change greater than or equal to to less that or equal to
anonymous
  • anonymous
what @misty1212 said
anonymous
  • anonymous
don't you divide by -1 and flip the sign?
misty1212
  • misty1212
lol multiply by -1, divide by -1, potato potahto
anonymous
  • anonymous
ok so would the domain be -1?
misty1212
  • misty1212
ooooh kay lets go slow
misty1212
  • misty1212
the domain is an interval right? not a number
anonymous
  • anonymous
Yes
misty1212
  • misty1212
the question is, what interval is it now we know that you cannot take the square root of a negative number, so the input has to be positive right?
misty1212
  • misty1212
the input in this case is \(-x\) in english we would say that \(-x\) must be greater than or equal to zero in math write \[-x\geq 0\]
misty1212
  • misty1212
to solve that for \(x\) change the sign so that it is \(x\) instead of \(-x\) and change the inequality as well
misty1212
  • misty1212
i.e \[-x\geq 0\iff x\leq 0\] and that is your domain
misty1212
  • misty1212
if you want to write it as an interval that works too, call it \[\huge (-\infty, 0]\]
anonymous
  • anonymous
Ok so what would the range be?
misty1212
  • misty1212
ok again we go slow the range is all possible outputs the square root is always greater than or equal to zero you have a minus sign in front, so that means the range will be all numbers less than or equal to zero
anonymous
  • anonymous
Ok so how would I graph it?
misty1212
  • misty1212
if you want to write it as an interval, write it the same as the domain in this case they are the same
misty1212
  • misty1212
how to you graph \(y=-\sqrt{-x}\)?
misty1212
  • misty1212
is that the question?
anonymous
  • anonymous
Well I have to sketch the graph of the function
anonymous
  • anonymous
do you know what \(y=\sqrt{x}\) looks like?
anonymous
  • anonymous
No
anonymous
  • anonymous
hmm then you can't really do it maybe look it up
anonymous
  • anonymous
ok
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=plot+y%3D%E2%88%92%E2%88%9A-x%3F
anonymous
  • anonymous
ok be very careful here
anonymous
  • anonymous
wolfram has given you too much information
anonymous
  • anonymous
where it says "complex valued plot" change it to "real valued plot"
anonymous
  • anonymous
Oh ok thanks
anonymous
  • anonymous
|dw:1440985596594:dw|you should see something like that

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