anonymous
  • anonymous
A circle is centered at (7, 8) and has a radius of 11. Which of the following is the equation for this circle? (x − 7)^2 + (y − 8)^2 = 121 (x − 7)^2 + (y − 8)^2 = 11 (x + 7)^2 + (y + 8)^2 = 121 (x + 7)^2 + (y + 8)^2 = 11
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
will donate medal to best answer
misty1212
  • misty1212
HI!!

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anonymous
  • anonymous
hi :)
misty1212
  • misty1212
make a guess, i bet you are right general form is \[(x-h)^2+(y-k)^2=r^2\] put \(h=7,k=8,r=11\)
anonymous
  • anonymous
so (x-7)^2+(y-8)^2=11^2 ?
misty1212
  • misty1212
yeah although they need you to square 11
anonymous
  • anonymous
ok
anonymous
  • anonymous
so (x^2+49)+(y+64)=121 ?
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
D:
anonymous
  • anonymous
oh no!!
anonymous
  • anonymous
can you help me ?
anonymous
  • anonymous
just take what you wrote above
anonymous
  • anonymous
\[(x-7)^2+(y-8)^2=11^2 \]
anonymous
  • anonymous
(x^2+49)+(y+64)=121 ?
anonymous
  • anonymous
all @misty1212 was saying is that in your answer choices the 11 is squared
anonymous
  • anonymous
so does that matter or not ?
freckles
  • freckles
are you trying to expand the square parts?
anonymous
  • anonymous
no it doesn't matter except for your answer choices
anonymous
  • anonymous
i dont know im bad at geometry
freckles
  • freckles
\[(x-7)^2=(x-7)(x-7)=x(x-7)-7(x-7)=x^2-7x-7x+49 \\ =x^2-14x+49\] no your choices do not have this form
anonymous
  • anonymous
im confused
anonymous
  • anonymous
D: D: D:
freckles
  • freckles
\[(x-h)^2+(y-k)^2=r^2 \\ \text{ you are give} (h,k)=(7,8) \text{ and } r=11 \\ \text{ just plug into this form }\] I think @satellite73 already walked you though this
freckles
  • freckles
replace h with 7 replace k with 8 replace r with 11
anonymous
  • anonymous
yes
anonymous
  • anonymous
(x-7)^2+(y-8)^2=121 ?
freckles
  • freckles
that is right
anonymous
  • anonymous
tnx u deserve the medal

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