anonymous
  • anonymous
Josh biked to school. In the morning, the traffic was light. So, he averaged 26 miles/hr to go to school. On the way back, his average speed is 20 miles/hr, and it took him 6 more minutes. How far is the school from Josh's house?
Mathematics
schrodinger
  • schrodinger
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Compassionate
  • Compassionate
Do know where to start?
anonymous
  • anonymous
Not at all Dx
triciaal
  • triciaal
do you know the relationship between distance speed and time

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triciaal
  • triciaal
are you here? please answer
anonymous
  • anonymous
Yes sorry @triciaal one minute is 1/60 hours
triciaal
  • triciaal
that is correct but that's not what I am asking
anonymous
  • anonymous
Oh, then the d=rt formula?
triciaal
  • triciaal
what is your r?
anonymous
  • anonymous
Is it 1/60
triciaal
  • triciaal
distance = speed* time
triciaal
  • triciaal
distance between 2 points will not change
triciaal
  • triciaal
|dw:1440990024964:dw|
triciaal
  • triciaal
|dw:1440990271320:dw|
anonymous
  • anonymous
So 26t=20(t+60)?
triciaal
  • triciaal
no look again
triciaal
  • triciaal
time is in hours 6 mins = 6/60 hrs
triciaal
  • triciaal
after you find the time then put in either expression and calculate d, distance from home to school
triciaal
  • triciaal
|dw:1440990821972:dw|
anonymous
  • anonymous
Were you supposed to simplify the 6/60 in the beginning? I just ended up with a bigger fraction
triciaal
  • triciaal
you did not show your work. I don't know what fraction you are talking about. 6 minutes is 6/60 = 1/10 hr always simplify fractions
triciaal
  • triciaal
do you understand the approach I used?
anonymous
  • anonymous
Ohhh ok I see what I did, I got the same answer when I simplified it. I get it now :) Thank you so much!
triciaal
  • triciaal
you are welcome

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