## anonymous one year ago Josh biked to school. In the morning, the traffic was light. So, he averaged 26 miles/hr to go to school. On the way back, his average speed is 20 miles/hr, and it took him 6 more minutes. How far is the school from Josh's house?

1. Compassionate

Do know where to start?

2. anonymous

Not at all Dx

3. triciaal

do you know the relationship between distance speed and time

4. triciaal

5. anonymous

Yes sorry @triciaal one minute is 1/60 hours

6. triciaal

that is correct but that's not what I am asking

7. anonymous

Oh, then the d=rt formula?

8. triciaal

9. anonymous

Is it 1/60

10. triciaal

distance = speed* time

11. triciaal

distance between 2 points will not change

12. triciaal

|dw:1440990024964:dw|

13. triciaal

|dw:1440990271320:dw|

14. anonymous

So 26t=20(t+60)?

15. triciaal

no look again

16. triciaal

time is in hours 6 mins = 6/60 hrs

17. triciaal

after you find the time then put in either expression and calculate d, distance from home to school

18. triciaal

|dw:1440990821972:dw|

19. anonymous

Were you supposed to simplify the 6/60 in the beginning? I just ended up with a bigger fraction

20. triciaal

you did not show your work. I don't know what fraction you are talking about. 6 minutes is 6/60 = 1/10 hr always simplify fractions

21. triciaal

do you understand the approach I used?

22. anonymous

Ohhh ok I see what I did, I got the same answer when I simplified it. I get it now :) Thank you so much!

23. triciaal

you are welcome