anonymous
  • anonymous
(3) 6 sqrt (ab^7)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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triciaal
  • triciaal
if you really need help please make sure your question is clear.
anonymous
  • anonymous
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mathstudent55
  • mathstudent55
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mathstudent55
  • mathstudent55
Since you are taking the 6th root, you need to find factors raised to the 6th power to be able to take them out of the root.
anonymous
  • anonymous
ah okay
mathstudent55
  • mathstudent55
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anonymous
  • anonymous
i have no idea @mathstudent55
mathstudent55
  • mathstudent55
Root and exponent are opposite operations. they cancel each other out. For example: For non-negative x and y \(\sqrt {x^2} = x\) \(\sqrt[3]{y^3} = y \) \(\large \sqrt[4] {x^4y^8} = \sqrt[4]{x^4 \cdot x^4 \cdot y^4} = \sqrt[4]{x^4} \cdot \sqrt[4]{x^4} \cdot \sqrt[4] {y^4} = x \cdot x \cdot y = x^2y\)
mathstudent55
  • mathstudent55
The sixth root of x^6 is simply x (for non-negative x).
anonymous
  • anonymous
oh so is it just 3b?
mathstudent55
  • mathstudent55
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mathstudent55
  • mathstudent55
The sixth root of b^6 is just b. That is correct, but the a and b are still inside the root.
mathstudent55
  • mathstudent55
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anonymous
  • anonymous
would that be the answer?
anonymous
  • anonymous
@mathstudent55
mathstudent55
  • mathstudent55
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