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anonymous

  • one year ago

(3) 6 sqrt (ab^7)

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  1. triciaal
    • one year ago
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    if you really need help please make sure your question is clear.

  2. anonymous
    • one year ago
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    |dw:1440987137279:dw|

  3. mathstudent55
    • one year ago
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    |dw:1440987334076:dw|

  4. mathstudent55
    • one year ago
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    Since you are taking the 6th root, you need to find factors raised to the 6th power to be able to take them out of the root.

  5. anonymous
    • one year ago
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    ah okay

  6. mathstudent55
    • one year ago
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    |dw:1440987416354:dw|

  7. anonymous
    • one year ago
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    i have no idea @mathstudent55

  8. mathstudent55
    • one year ago
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    Root and exponent are opposite operations. they cancel each other out. For example: For non-negative x and y \(\sqrt {x^2} = x\) \(\sqrt[3]{y^3} = y \) \(\large \sqrt[4] {x^4y^8} = \sqrt[4]{x^4 \cdot x^4 \cdot y^4} = \sqrt[4]{x^4} \cdot \sqrt[4]{x^4} \cdot \sqrt[4] {y^4} = x \cdot x \cdot y = x^2y\)

  9. mathstudent55
    • one year ago
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    The sixth root of x^6 is simply x (for non-negative x).

  10. anonymous
    • one year ago
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    oh so is it just 3b?

  11. mathstudent55
    • one year ago
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    |dw:1440988089264:dw|

  12. mathstudent55
    • one year ago
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    The sixth root of b^6 is just b. That is correct, but the a and b are still inside the root.

  13. mathstudent55
    • one year ago
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    |dw:1440988135319:dw|

  14. anonymous
    • one year ago
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    would that be the answer?

  15. anonymous
    • one year ago
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    @mathstudent55

  16. mathstudent55
    • one year ago
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    |dw:1440989078538:dw|

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