## anonymous one year ago (3) 6 sqrt (ab^7)

1. triciaal

if you really need help please make sure your question is clear.

2. anonymous

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3. mathstudent55

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4. mathstudent55

Since you are taking the 6th root, you need to find factors raised to the 6th power to be able to take them out of the root.

5. anonymous

ah okay

6. mathstudent55

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7. anonymous

i have no idea @mathstudent55

8. mathstudent55

Root and exponent are opposite operations. they cancel each other out. For example: For non-negative x and y $$\sqrt {x^2} = x$$ $$\sqrt[3]{y^3} = y$$ $$\large \sqrt[4] {x^4y^8} = \sqrt[4]{x^4 \cdot x^4 \cdot y^4} = \sqrt[4]{x^4} \cdot \sqrt[4]{x^4} \cdot \sqrt[4] {y^4} = x \cdot x \cdot y = x^2y$$

9. mathstudent55

The sixth root of x^6 is simply x (for non-negative x).

10. anonymous

oh so is it just 3b?

11. mathstudent55

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12. mathstudent55

The sixth root of b^6 is just b. That is correct, but the a and b are still inside the root.

13. mathstudent55

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14. anonymous

15. anonymous

@mathstudent55

16. mathstudent55

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