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IrishBoy123
 one year ago
complex
IrishBoy123
 one year ago
complex

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0for z = 2, find M such that: \[\left \frac{z^2  4z3}{(z^27)(z^2+2} \right \le M\]

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0\[\left \frac{z^2  4z 3}{(z^2  7)(z^2 + 2)} \right\] \[= \frac{z^2  4z 3}{z^2  7 \ z^2 + 2}\] from Triangle Inequality \[ z^2  (7)  \le z^2 + ( 7) \le z^2 + 7\] \[ 3 \le z^2  7 \le 11\] \[ z^2  2  \le z^2 + 2 \le z^2 + 2\] \[ 2 \le z^2  2 \le 6\] \[ z^2  4z  3) \le z^2 + 4z + 3 = 4 + 8 + 3 = 15\] \[\frac{15}{3 \times 2} = \frac{5}{2} = M\]
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