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Zale101
 one year ago
Find the magnitude of the resultant force and the angle that makes with the positive xaxis
Zale101
 one year ago
Find the magnitude of the resultant force and the angle that makes with the positive xaxis

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Zale101
 one year ago
Best ResponseYou've already chosen the best response.2\(F1=75 N; θ=0\) \(F2=50 N; θ=30\) \(F3=40 N; θ=150\) F1= \(f_1x=75cos(0)=75 N\) \(f_1y=75sin(0)=0 N\) F2= \(f_2x=50cos(30)=25\sqrt{3} N\) \(f_2y=50sin(30)=25 N\) F3= \(f_3x=40cos(150)=−20\sqrt{2}N\) \(f_3y=40sin(150)=20 N\)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I don't agree with f3x

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1everything else looks good

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Looks good! next simply add them component by component

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Ahh I didn't check the arithmetic..

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1this should fix it : \(F1=75 N; θ=0\) \(F2=50 N; θ=30\) \(F3=40 N; θ=150\) F1= \(f_1x=75cos(0)=75 N\) \(f_1y=75sin(0)=0 N\) F2= \(f_2x=50cos(30)=25\sqrt{3} N\) \(f_2y=50sin(30)=25 N\) F3= \(f_3x=40cos(150)=−20\sqrt{\color{red}{3}}N\) \(f_3y=40sin(150)=20 N\)

Zale101
 one year ago
Best ResponseYou've already chosen the best response.2Okay. Thanks! @jim_thompson5910 and @ganeshie8 !!! I'll deal with the arithmetic, it's not the problem for me now. But the next step is what i'm having problems with.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you have the vector components, add up the corresponding components

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1u = <a,b> v = <c,d> w = <e,f> u+v+w = <a+c+e, b+d+f>

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440991132300:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440991352564:dw

Zale101
 one year ago
Best ResponseYou've already chosen the best response.2Okay, thanks. makes sense !

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you'll end up with some vector z = <p,q> p = sum of the Fx q = sum of the Fy magnitude of z = z = sqrt(p^2 + q^2)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1theta = arctan(q/p)

Zale101
 one year ago
Best ResponseYou've already chosen the best response.2Oh yes. I forgot about that xD

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1theta = arctan(q/p) if theta is in Q1 or Q4 theta = arctan(q/p)+180 if theta is in Q2 or Q3

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1to figure out which quadrant theta is in, simply look at the vector <p,q>

Zale101
 one year ago
Best ResponseYou've already chosen the best response.2Absolutely. Alright thanks for all the help.
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