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anonymous

  • one year ago

Evaluate cot 45° without using a calculator by using ratios in a reference triangle.

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  1. madhu.mukherjee.946
    • one year ago
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    |dw:1440990907999:dw|

  2. anonymous
    • one year ago
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    \[\theta = 45 \] right?

  3. madhu.mukherjee.946
    • one year ago
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    yeah

  4. madhu.mukherjee.946
    • one year ago
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    so now tan theta=perpendicular/base

  5. anonymous
    • one year ago
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    okay so i need to get cot 45°, what two would i have to use

  6. anonymous
    • one year ago
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    ohh ok

  7. anonymous
    • one year ago
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    \[\frac{ \sqrt{2} }{ 1 }\]

  8. madhu.mukherjee.946
    • one year ago
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    no

  9. madhu.mukherjee.946
    • one year ago
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    1/1 =1

  10. anonymous
    • one year ago
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    ok sorry

  11. madhu.mukherjee.946
    • one year ago
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    so cot is the inverse of tan so cot 45=1/tan 45 =1/1=1

  12. madhu.mukherjee.946
    • one year ago
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    |dw:1440991228256:dw|

  13. anonymous
    • one year ago
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    okay so i can say that i got the perpendicular/base and i imputed the values, which were 1/1, resulting in one, which is 1/tan45°, the inverse of cot 45°

  14. madhu.mukherjee.946
    • one year ago
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    yeah

  15. anonymous
    • one year ago
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    should i say cos45sin45=cot45

  16. anonymous
    • one year ago
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    cos45 = 1/sqrt2 sin45 = 1/sqrt2 cot45 = 1/tan45 tan45 = (1/sqrt2)/(1/sqrt2) = 1 so cot45 = 1/tan45 = 1/1 = 1

  17. anonymous
    • one year ago
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    or should i just leave my explanation as is

  18. madhu.mukherjee.946
    • one year ago
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    nope just say as much i told you

  19. madhu.mukherjee.946
    • one year ago
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    don't say this sin cos thing

  20. anonymous
    • one year ago
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    okay, thank you!

  21. jim_thompson5910
    • one year ago
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    @DanTheMan99 if I were answering, I'd just say cot(angle) = adjacent/opposite cot(45) = 1/1 cot(45) = 1 |dw:1440991725602:dw|

  22. anonymous
    • one year ago
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    thanks

  23. madhu.mukherjee.946
    • one year ago
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    your welcome

  24. madhu.mukherjee.946
    • one year ago
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    |dw:1440991586753:dw| so just erase this concept out of your head

  25. anonymous
    • one year ago
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    whats the other side called? not the perpendicular nor the base?

  26. anonymous
    • one year ago
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    ^thanks for that

  27. madhu.mukherjee.946
    • one year ago
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    its the hypotenuse

  28. madhu.mukherjee.946
    • one year ago
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    your welcome

  29. anonymous
    • one year ago
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    thank you, so i say i got the base and the perpendicular as the opposite/ adjacent

  30. madhu.mukherjee.946
    • one year ago
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    yeah

  31. anonymous
    • one year ago
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    thanks

  32. madhu.mukherjee.946
    • one year ago
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    i'll tell you a rhyme which my teacher taught .this will help you to remember the trigonometric ratios

  33. anonymous
    • one year ago
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    cot 45° = 1/ tan45° I need to get 1/ tan45°, i get the perpendicular/base with the opposite =1 with the adjacent =1 with the hypotenuse = Square root 2 i got opposite/ adjacent which resulted in 1/1(one), which is cot 45° do you think this is good

  34. mathstudent55
    • one year ago
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    |dw:1440991925029:dw|

  35. madhu.mukherjee.946
    • one year ago
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    |dw:1440991800604:dw|learn this rhyme by heart and you'll never forget trigonometry.the underlined portion is the rhyme:)

  36. anonymous
    • one year ago
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    thank you!

  37. madhu.mukherjee.946
    • one year ago
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    your welcome:)

  38. mathstudent55
    • one year ago
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    Alternatively, you can remember SOH CAH TOA sin=opp/hyp cos=adj/hyp tan=opp/adj

  39. anonymous
    • one year ago
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    thanks

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