anonymous
  • anonymous
Evaluate cot 45° without using a calculator by using ratios in a reference triangle.
Mathematics
katieb
  • katieb
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madhu.mukherjee.946
  • madhu.mukherjee.946
|dw:1440990907999:dw|
anonymous
  • anonymous
\[\theta = 45 \] right?
madhu.mukherjee.946
  • madhu.mukherjee.946
yeah

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madhu.mukherjee.946
  • madhu.mukherjee.946
so now tan theta=perpendicular/base
anonymous
  • anonymous
okay so i need to get cot 45°, what two would i have to use
anonymous
  • anonymous
ohh ok
anonymous
  • anonymous
\[\frac{ \sqrt{2} }{ 1 }\]
madhu.mukherjee.946
  • madhu.mukherjee.946
no
madhu.mukherjee.946
  • madhu.mukherjee.946
1/1 =1
anonymous
  • anonymous
ok sorry
madhu.mukherjee.946
  • madhu.mukherjee.946
so cot is the inverse of tan so cot 45=1/tan 45 =1/1=1
madhu.mukherjee.946
  • madhu.mukherjee.946
|dw:1440991228256:dw|
anonymous
  • anonymous
okay so i can say that i got the perpendicular/base and i imputed the values, which were 1/1, resulting in one, which is 1/tan45°, the inverse of cot 45°
madhu.mukherjee.946
  • madhu.mukherjee.946
yeah
anonymous
  • anonymous
should i say cos45sin45=cot45
anonymous
  • anonymous
cos45 = 1/sqrt2 sin45 = 1/sqrt2 cot45 = 1/tan45 tan45 = (1/sqrt2)/(1/sqrt2) = 1 so cot45 = 1/tan45 = 1/1 = 1
anonymous
  • anonymous
or should i just leave my explanation as is
madhu.mukherjee.946
  • madhu.mukherjee.946
nope just say as much i told you
madhu.mukherjee.946
  • madhu.mukherjee.946
don't say this sin cos thing
anonymous
  • anonymous
okay, thank you!
jim_thompson5910
  • jim_thompson5910
@DanTheMan99 if I were answering, I'd just say cot(angle) = adjacent/opposite cot(45) = 1/1 cot(45) = 1 |dw:1440991725602:dw|
anonymous
  • anonymous
thanks
madhu.mukherjee.946
  • madhu.mukherjee.946
your welcome
madhu.mukherjee.946
  • madhu.mukherjee.946
|dw:1440991586753:dw| so just erase this concept out of your head
anonymous
  • anonymous
whats the other side called? not the perpendicular nor the base?
anonymous
  • anonymous
^thanks for that
madhu.mukherjee.946
  • madhu.mukherjee.946
its the hypotenuse
madhu.mukherjee.946
  • madhu.mukherjee.946
your welcome
anonymous
  • anonymous
thank you, so i say i got the base and the perpendicular as the opposite/ adjacent
madhu.mukherjee.946
  • madhu.mukherjee.946
yeah
anonymous
  • anonymous
thanks
madhu.mukherjee.946
  • madhu.mukherjee.946
i'll tell you a rhyme which my teacher taught .this will help you to remember the trigonometric ratios
anonymous
  • anonymous
cot 45° = 1/ tan45° I need to get 1/ tan45°, i get the perpendicular/base with the opposite =1 with the adjacent =1 with the hypotenuse = Square root 2 i got opposite/ adjacent which resulted in 1/1(one), which is cot 45° do you think this is good
mathstudent55
  • mathstudent55
|dw:1440991925029:dw|
madhu.mukherjee.946
  • madhu.mukherjee.946
|dw:1440991800604:dw|learn this rhyme by heart and you'll never forget trigonometry.the underlined portion is the rhyme:)
anonymous
  • anonymous
thank you!
madhu.mukherjee.946
  • madhu.mukherjee.946
your welcome:)
mathstudent55
  • mathstudent55
Alternatively, you can remember SOH CAH TOA sin=opp/hyp cos=adj/hyp tan=opp/adj
anonymous
  • anonymous
thanks

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