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Jamierox4ev3r
 one year ago
Check my work someone, not sure if I'm going about this in the correct manner
Jamierox4ev3r
 one year ago
Check my work someone, not sure if I'm going about this in the correct manner

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Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2Give me a second to type out the problem, thank you

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2Simplify the rational expression: \(\Large\frac{10^{2}+29x+21}{x^{2}25}\times\frac{x+5}{2x+3}\)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2So far, I've factored the top portion. So \(10x^{2}+29x+21\) should turn into (5x+7)(2x+3) while \(x^{2}25\) should be (x5)(x+5)

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2*factored both the numerator and denominator of the first part of the expression

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2So I tried crossmultiplying, but that brought me more complications...however, I noticed a few things \(\huge\frac{(5x7)(2x+3)}{(x5)(x+5)}\times\frac{x+5}{2x+3}\) \(\huge\frac{(5x7)\color{red}{(2x+3)}}{(x5)\color{red}{(x+5)}}\times\frac{\color{red}{x+5}}{\color{red}{2x+3}}\) Can the things in red cancel out? And would that lead me with a final answer?

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2^This is where there are some clear holes in my recollection of simplifying. Someone clarify my thinking, thanks

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2you are correct. The `2x+3` terms will divide to 1 and effectively go away since 1*(any number) = same number the same applies to the `x+5` terms

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2so \(\huge\frac{5x+7}{x5}\) would be final answer? I mean, I'm not sure if that could be simplified any further, but I don't think so.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2that's as simplified as it gets

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.2Hmm alright. Thank you for your time :)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2you're welcome
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