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Jamierox4ev3r
 one year ago
Find the composition of f(g(x)), when
f(x)=7x^22x+9 and
g(x)=x4
Simplify
Jamierox4ev3r
 one year ago
Find the composition of f(g(x)), when f(x)=7x^22x+9 and g(x)=x4 Simplify

This Question is Closed

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1I have a pretty clear idea of how to go about doing this, so I'll just show all of my process. I'll also point out the one small detail that I had a bit of doubt on.

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1\(7(x4)^{2}2(x4)+9\) \(7(x4)(x4)2x+8+9\) \((7x28)(x4)2x+17\) \(7x^{2}28x28x+1122x+17\) \(7x^{2}58x+129\) ^^ I believe this is correct...but I forget the rules on difference of squares. does (x2)^2 turn into (x2)(x2) or (x2)(x+2) ?? Also, do I need to factor the final answer?

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0try and see if it can be done,then its good

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1see it what can be done?

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0i don't think it can be factored

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1x^2 means x times x anything squared is that number multiplied by itself so (x2)^2 means (x2) times (x2)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large 7x^{2}58x+129\] is the correct final answer

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1Oh. You're referring to my question on whether it could be factor or not. oh and @jim_thompson5910 , so in the problem, if you look at my work, my assumption was indeed that (x2)^2 was (x2)(x2). Thank you! I thought I remembered some funky rule from early high school about difference of squares or something like that. So I was correct all along. Wow I overthought this. Thank again!

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you're thinking of a^2  b^2 = (ab)(a+b)

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0its perfectly all right

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0u can solve it by the formula

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1Oh okay. These rules are so easy to get confused, especially when trying to recall from memory

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0this formula is known as the SRIDHAR ACHARYA formula

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0don't worry by this formula it will get easy

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0put 7x^58x+129 in this formula

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1Don't you mean the quadratic formula? And yes, I know that you can use the quadratic formula to factor. Problem is, I see now that when I use the quadratic formula, the roots are imaginary. Therefore, This cannot be factored any further. Jim's answer is the final answer

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1@madhu.mukherjee.946 thanks for trying to help, but I fully understand now. I've used the quadratic formula before, and I understand what it does \(\ddot\smile\)

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0okay.your welcome

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1You can use the discriminant formula as a shorter way to see if you can factor or not if D = b^2  4ac is a perfect square and a positive number, then you can factor

Jamierox4ev3r
 one year ago
Best ResponseYou've already chosen the best response.1Woah, that's a helpful tip. *cough* I have a program in my calculator that solves all quadratics for me, so that's how I knew that the roots would be imaginary. But when in a pinch, when without a calculator, this is an extremely convenient tip. Thanks for bringing that back into my memory

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1definitely a handy thing to have

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you're welcome
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