anonymous
  • anonymous
can someone help me with simplifying radical expressions? 1/sqrt(x)+sqrt(y)
Calculus1
katieb
  • katieb
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anonymous
  • anonymous
|dw:1440999970186:dw|
madhu.mukherjee.946
  • madhu.mukherjee.946
|dw:1441000576022:dw|
jim_thompson5910
  • jim_thompson5910
multiply top and bottom by \[\Large \sqrt{x}-\sqrt{y}\] |dw:1441000755361:dw|

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jim_thompson5910
  • jim_thompson5910
why do this? because you will take advantage of the fact that (a-b)(a+b) = a^2 - b^2 squaring the square root will cancel out the square root eg: \[\Large (\sqrt{x})^2 = x\] where is nonnegative
madhu.mukherjee.946
  • madhu.mukherjee.946
so where did i go wrong
jim_thompson5910
  • jim_thompson5910
you didn't make a mistake @madhu.mukherjee.946 \[\Large \frac{1}{\sqrt{x}+\sqrt{y}} = \frac{\sqrt{x}-\sqrt{y}}{x-y}\] is true assuming \(\Large x \ne y\) and neither x nor y are zero
madhu.mukherjee.946
  • madhu.mukherjee.946
thanks
madhu.mukherjee.946
  • madhu.mukherjee.946
so @Mando98 your sum is solved
anonymous
  • anonymous
so the final answer is |dw:1441001112100:dw|
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
thank you and do you think you could help me out with 2 more problems (similar to this one)?
jim_thompson5910
  • jim_thompson5910
sure just post them as separate posts to avoid clutter
madhu.mukherjee.946
  • madhu.mukherjee.946
dude where's the medal

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