anonymous one year ago $$\sf 16x^2 - 24x+7 = 0$$

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1. Abhisar

Use the quadratic formula, $$\sf x = \huge \frac{-b\pm\sqrt{b^2-4ac}}{2a}$$

2. sepeario

When using the quadratic formula, remember that you are using a quadratic in the form of ax^2 + bx + c = 0. So in your quadratic that has been given, a=16, b=-24 c=7.

3. sepeario

Can you substitute those values into the given equation above?