anonymous
  • anonymous
Can someone please help me simplify these radical expressions? Screen shots included! Medal and fan!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
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sohailiftikhar
  • sohailiftikhar
ok wright first one \[\sqrt{45n^5}\]
anonymous
  • anonymous
3√6 √n^5

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anonymous
  • anonymous
3√5***
sohailiftikhar
  • sohailiftikhar
now split the expression ... yes it will be 3 n^2\[\sqrt{5n}\]
sohailiftikhar
  • sohailiftikhar
\[3n^2 \sqrt{5n}\]
sohailiftikhar
  • sohailiftikhar
now take second .. \[\sqrt{75}+\sqrt{3}\]
anonymous
  • anonymous
ok
sohailiftikhar
  • sohailiftikhar
\[\sqrt{25\times 3}+\sqrt{3}\]
sohailiftikhar
  • sohailiftikhar
\[5\sqrt{3}+\sqrt{3}\]
sohailiftikhar
  • sohailiftikhar
now what you think?
anonymous
  • anonymous
wait we're on problem 2 now? you simplified √25x 3?
sohailiftikhar
  • sohailiftikhar
yes
sohailiftikhar
  • sohailiftikhar
\[\sqrt{75}=5\sqrt{3}\]
sohailiftikhar
  • sohailiftikhar
so \[\sqrt{75}+\sqrt{3}=5\sqrt{3}+\sqrt{3}=6\sqrt{3}\]
anonymous
  • anonymous
ohh ok
sohailiftikhar
  • sohailiftikhar
now take third ..
anonymous
  • anonymous
wait
sohailiftikhar
  • sohailiftikhar
what ?
anonymous
  • anonymous
So this is correct? 6.) √75 + √3 √25 * 3 + √3 5√3 + √3 = 6√3
anonymous
  • anonymous
Okay now for 3
sohailiftikhar
  • sohailiftikhar
can you do it ?
sohailiftikhar
  • sohailiftikhar
ok
anonymous
  • anonymous
@sohailiftikhar sorry I lost connection please help me with the last one
UnkleRhaukus
  • UnkleRhaukus
are you up to question 7)?
anonymous
  • anonymous
yes @UnkleRhaukus
UnkleRhaukus
  • UnkleRhaukus
\[\sqrt7(\sqrt{14}+\sqrt3)\]factor the 14
UnkleRhaukus
  • UnkleRhaukus
like 75 factors to be 3*25
UnkleRhaukus
  • UnkleRhaukus
14 = ? * ?
UnkleRhaukus
  • UnkleRhaukus
what numbers multiply to equal 14?
anonymous
  • anonymous
or factoring = breaking it down
anonymous
  • anonymous
2*7 lol
UnkleRhaukus
  • UnkleRhaukus
\[\sqrt7(\sqrt{14}+\sqrt3)\\ =\sqrt7(\sqrt{2\times7}+\sqrt3)\\ =\sqrt7(\sqrt2\sqrt7+\sqrt3)\\ =\] now distribute. (multiply the term out the front of the parentheses, by all the terms inside )
UnkleRhaukus
  • UnkleRhaukus
huh?
sohailiftikhar
  • sohailiftikhar
so you here ?

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