Block B in the figure weighs 752 N. The coefficient of static friction between block and table is 0.32; angle θ is 33°; assume that the cord between B and the knot is horizontal. Find the maximum weight of block A for which the system will be stationary.

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Block B in the figure weighs 752 N. The coefficient of static friction between block and table is 0.32; angle θ is 33°; assume that the cord between B and the knot is horizontal. Find the maximum weight of block A for which the system will be stationary.

Mathematics
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|dw:1441019774244:dw| Nice problem. Does the above completed figure correspond to what was intended?
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hey! sorry for the late reply, yes, that is the problem
is 0.32 coefficient of friction? how do i do that?
|dw:1441020009343:dw| Set up the equations: equilibrium at the knot: \(mg = T ~tan(\theta)\) At the point of movement, \(\mu~Mg=T\) Solve for m.
oh, thanks but i meant how did you solve for that, and how did you get 0.32?
The coefficient of static friction is the ratio of the maximum friction force and the normal reaction between two objects when neither of the objects is moving. (ref. wiki plus corrections)
It's given in the question: "The coefficient of static friction between block and table is 0.32; "
oh! i did not see that sorry
thanks haha
You're welcome! :)
wait ill try to solve
Post your answer for checking if you wish. I may be offline, but may be back later. I'll bet someone else will jump in to help! :)
ok thanks again!
hey i got the answer! thanks! @musicmate
Can you post your answer if you want to check?
it's 156.27. but it already said that the answer was correct haha

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