## 1018 one year ago Block B in the figure weighs 752 N. The coefficient of static friction between block and table is 0.32; angle θ is 33°; assume that the cord between B and the knot is horizontal. Find the maximum weight of block A for which the system will be stationary.

1. 1018

|dw:1441017490655:dw|

2. mathmate

|dw:1441019774244:dw| Nice problem. Does the above completed figure correspond to what was intended?

3. mathmate

|dw:1441019918401:dw|

4. 1018

hey! sorry for the late reply, yes, that is the problem

5. 1018

is 0.32 coefficient of friction? how do i do that?

6. mathmate

|dw:1441020009343:dw| Set up the equations: equilibrium at the knot: $$mg = T ~tan(\theta)$$ At the point of movement, $$\mu~Mg=T$$ Solve for m.

7. 1018

oh, thanks but i meant how did you solve for that, and how did you get 0.32?

8. mathmate

The coefficient of static friction is the ratio of the maximum friction force and the normal reaction between two objects when neither of the objects is moving. (ref. wiki plus corrections)

9. mathmate

It's given in the question: "The coefficient of static friction between block and table is 0.32; "

10. 1018

oh! i did not see that sorry

11. 1018

thanks haha

12. mathmate

You're welcome! :)

13. 1018

wait ill try to solve

14. mathmate

Post your answer for checking if you wish. I may be offline, but may be back later. I'll bet someone else will jump in to help! :)

15. 1018

ok thanks again!

16. 1018

hey i got the answer! thanks! @musicmate

17. mathmate

Can you post your answer if you want to check?

18. 1018

it's 156.27. but it already said that the answer was correct haha