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Show your work, please.
Want to take a trick?
Ok, so I tried a couple ways. First way: I drew a rough graph to find where the line goes through the y axis using the points given and the gradient 2, I found that it goes through -2. Then I put this information into the form y=mx + c and got y=2x-2
Mistake: the given line has slope m= -2/3, not 2
Take my trick, ok?
Oh wow. Well that just made everything like 10 times easier.
One last thing though...
Notes: For parallel lines only.
In some of the answer to this type of equation they rearrange it (to give it in the kind of form as 2x + 3y=10 ) and sometimes they dont. For example: say I just found the equation of a line and it is y=-1/5x-1 , how do I know if thats the answer or if it needs to be rerranged to give x+5y+5=0 ?
Ok, noted. Thanks
In this case, you move x, y to one side, number in other side, then you get the right form to apply.
Ok, must I always do that?
it is not a must, but it makes the stuff easier.
The only thing I am concerned about is that I am trying to do that where it can't be done. A couple times I tried to do that and then gave it in the wrong form because of it.
I mean, one of the answers was in the original form of y=mx +c (it was y=3x-14) so they didn't do it then. Why are they doing it for some and not for others?
Give me the whole thing, I will work it in neat for you as an example
Thank you so much, ok...
parallel to 3x - y - 1=0 and passing through (4,-2)
hey, it is easy, just move x, y to one side and number to another side 3x - y =1 then replace the point in ( ignore the right hand side) 3*(4) - (-2) = 14 hence the required line is 3x -y = 14 then move back to original form 3x -y -14 =0
Ok, thank you very much! I think I understand now, that has helped me rather a lot. Have a nice day!