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anonymous
 one year ago
find the equations of the following line:
(v) parallel to 2x+3y=4 and passing through (2,2)
I got the answer y=2x2 but the answer the book gives is 2x + 3y=10 . Please can you help me by telling me the proper method to find out the answer! Also I realize that you had to rearrange the equation, but what dictates when you have to and when you don't?
anonymous
 one year ago
find the equations of the following line: (v) parallel to 2x+3y=4 and passing through (2,2) I got the answer y=2x2 but the answer the book gives is 2x + 3y=10 . Please can you help me by telling me the proper method to find out the answer! Also I realize that you had to rearrange the equation, but what dictates when you have to and when you don't?

This Question is Closed

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0Show your work, please.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, so I tried a couple ways. First way: I drew a rough graph to find where the line goes through the y axis using the points given and the gradient 2, I found that it goes through 2. Then I put this information into the form y=mx + c and got y=2x2

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0Mistake: the given line has slope m= 2/3, not 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh wow. Well that just made everything like 10 times easier.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0One last thing though...

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0Notes: For parallel lines only.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0In some of the answer to this type of equation they rearrange it (to give it in the kind of form as 2x + 3y=10 ) and sometimes they dont. For example: say I just found the equation of a line and it is y=1/5x1 , how do I know if thats the answer or if it needs to be rerranged to give x+5y+5=0 ?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0In this case, you move x, y to one side, number in other side, then you get the right form to apply.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, must I always do that?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0it is not a must, but it makes the stuff easier.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The only thing I am concerned about is that I am trying to do that where it can't be done. A couple times I tried to do that and then gave it in the wrong form because of it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I mean, one of the answers was in the original form of y=mx +c (it was y=3x14) so they didn't do it then. Why are they doing it for some and not for others?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0Give me the whole thing, I will work it in neat for you as an example

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much, ok...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0parallel to 3x  y  1=0 and passing through (4,2)

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0hey, it is easy, just move x, y to one side and number to another side 3x  y =1 then replace the point in ( ignore the right hand side) 3*(4)  (2) = 14 hence the required line is 3x y = 14 then move back to original form 3x y 14 =0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, thank you very much! I think I understand now, that has helped me rather a lot. Have a nice day!
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