At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

That would be the sin function right?

yep

\[\sin(x)=\frac{OT}{OB}\]

After simplifying the ratio, you can use a calculator

Okay wouldn't it be sin (x) = 200/900?

yep!

Okay, then I'd divide 200 into 900 right?

Wait.. What're you saying @welshfella

no you divide 900 into 200

was the diagram given in the question?

\[\sin(x)=\frac{200}{900}=\frac{2}{9}\]

|dw:1441025224072:dw|

Okay, so 200 is the distance then?

Since T is 200.

yep, it looks like that is the case

Yes, this is the exact picture for the question:

Oh OK then you are on right track The picture is correct but the question has an error.

Okay well if T is the distance should I still use the sin function for 200/900?

yes
Nishant's formula is correct

use a calculator to find arcsin of 200/900, make sure to convert it to degrees if it's in radians

12.838 approximately 12.84, that's perfect you got your answer there

it was already in degrees you didn't need to convert it

Oh okay! So everything works out then?

yep you've done the question

Thank you for all your help!