A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
FAN AND MEDAL
anonymous
 one year ago
FAN AND MEDAL

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A closed container has 2.04 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10−24 grams. Which of the following shows and explains the approximate total mass, in grams, of all the atoms of the gas in the container? 0.34 grams, because (2.04 ⋅ 1.67) ⋅ (1023 ⋅ 10−24) = 3.4068 ⋅ 10−1 0.37 grams, because (2.04 + 1.67) ⋅ (1023 ⋅ 10−24) = 3.71 ⋅ 10−1 3.41 grams, because (2.04 ⋅ 1.67) ⋅ (1023 ⋅ 10−24) = 3.4068 3.71 grams, because (2.04 + 1.67) ⋅ (1023 ⋅ 10−24) = 3.71

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Compare the decimals 56.07 and 56.7. Which comparison is correct? A. 56.07 > 56.7 B. 56.07 = 56.7 C. 56.07 < 56.7

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@iwillpraise you can not put ur question on someone else problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@kiamousekia 1 mole of H weights 1.008 g 1 mole = 6.02 x 10^23 particles Mass of 1 atom = 1.008 g / 6.02 x 10^23 = 1.67 x 10^24 g

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Lol that's real helpful

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Soooooo... 2.04x10^23 atoms x 1.67x10^24 g/atom = 3.41x10^1 g

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and your Right its right its C
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.