zarkam21
  • zarkam21
PLease help ! :p
Mathematics
jamiebookeater
  • jamiebookeater
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

zarkam21
  • zarkam21
1 Attachment
tkhunny
  • tkhunny
What are the criteria for identifying outliers? Some ratio of some other piece of the puzzle?
zarkam21
  • zarkam21
I don't know lol, thats why I need help

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

tkhunny
  • tkhunny
Your course materials or your instruct should give you that information. Opinions vary. Show your work. What do you find in your materials?
tkhunny
  • tkhunny
Often 1.5 * IQR
zarkam21
  • zarkam21
One definition of outlier is any data point more than 1.5 interquartile ranges (IQRs) below the first quartile or above the third quartile. Note: The IQR definition given here is widely used but is not the last word in determining whether a given number is an outlier. IQR = 10.5 – 3.5 = 7, so 1.5. IQR = 10.5.
zarkam21
  • zarkam21
Got this from google
texaschic101
  • texaschic101
first we need to find the IQR.....which is Q3 - Q1 89.3 - 73.4 = 15.9 to find an outlier : if a date point lies below Q1 - (1.5 * IQR) or above Q3 + (1.5 * IQR) below : 73.4 - (1.5 * 15.9) = 73.4 - 23.85 = 49.55 above 89.3 + (1.5 * 15.9) = 89.3 + 23.85 = 113.15 So if you have data points below 49.55 and above 113.15, then these are your outliers. And if you look at your first number, 4.8 ....it is below 49.55....so yes, there is an outlier

Looking for something else?

Not the answer you are looking for? Search for more explanations.