anonymous
  • anonymous
WILL FAN AND MEDAL PLEASE HELP.
Geometry
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anonymous
  • anonymous
WILL FAN AND MEDAL PLEASE HELP.
Geometry
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
I don't even know where to start with this, but I will tag a few people perhaps they can help.
anonymous
  • anonymous
Thank you.

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anonymous
  • anonymous
anonymous
  • anonymous
NP hopefully they can help you.
anonymous
  • anonymous
anonymous
  • anonymous
I can try.. but im too sure
anonymous
  • anonymous
It'd be nice but if you aren't sure then you don't have to.
anonymous
  • anonymous
no its fine I can try
anonymous
  • anonymous
I believe its the 3rd o 4th choice but Im not really sure but for those 2 , maybe see if @Nnesha or @geny55 can help , sorry
anonymous
  • anonymous
No need to be sorry. I appreciate your trying though.
anonymous
  • anonymous
anonymous
  • anonymous
whats the question?
anonymous
  • anonymous
It's attached in the first comment
anonymous
  • anonymous
im gonna say 164 38/63
anonymous
  • anonymous
That wasn't right :/
anonymous
  • anonymous
try the bottom one insufficient information
anonymous
  • anonymous
I can't I only get one try per question. Would you try one more though?
raiders88
  • raiders88
hmmm its tricky
anonymous
  • anonymous
Can one of you please help my friend? @Astrophysics @IrishBoy123
IrishBoy123
  • IrishBoy123
the arc is \(100^o\) compared to a max \(360^o\) for a full circle
IrishBoy123
  • IrishBoy123
then ask, if it was a full circle what would be circumference?
IrishBoy123
  • IrishBoy123
then work out \(\frac{100}{360}\) 'ths of that amount

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