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anonymous

  • one year ago

WILL FAN AND MEDAL PLEASE HELP.

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    I don't even know where to start with this, but I will tag a few people perhaps they can help.

  3. anonymous
    • one year ago
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    Thank you.

  4. anonymous
    • one year ago
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    @arindameducationusc @ganeshie8

  5. anonymous
    • one year ago
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    NP hopefully they can help you.

  6. anonymous
    • one year ago
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    @Bella108

  7. anonymous
    • one year ago
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    I can try.. but im too sure

  8. anonymous
    • one year ago
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    It'd be nice but if you aren't sure then you don't have to.

  9. anonymous
    • one year ago
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    no its fine I can try

  10. anonymous
    • one year ago
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    I believe its the 3rd o 4th choice but Im not really sure but for those 2 , maybe see if @Nnesha or @geny55 can help , sorry

  11. anonymous
    • one year ago
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    No need to be sorry. I appreciate your trying though.

  12. anonymous
    • one year ago
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    @shady580

  13. anonymous
    • one year ago
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    whats the question?

  14. anonymous
    • one year ago
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    It's attached in the first comment

  15. anonymous
    • one year ago
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    im gonna say 164 38/63

  16. anonymous
    • one year ago
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    That wasn't right :/

  17. anonymous
    • one year ago
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    try the bottom one insufficient information

  18. anonymous
    • one year ago
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    I can't I only get one try per question. Would you try one more though?

  19. raiders88
    • one year ago
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    hmmm its tricky

  20. anonymous
    • one year ago
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    Can one of you please help my friend? @Astrophysics @IrishBoy123

  21. IrishBoy123
    • one year ago
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    the arc is \(100^o\) compared to a max \(360^o\) for a full circle

  22. IrishBoy123
    • one year ago
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    then ask, if it was a full circle what would be circumference?

  23. IrishBoy123
    • one year ago
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    then work out \(\frac{100}{360}\) 'ths of that amount

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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