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anonymous

  • one year ago

find limx→π+ csc(2x) is it positive or a negative limit?

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  1. anonymous
    • one year ago
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    \[\lim_{x \rightarrow \pi} \csc(2x)\] written like this ?

  2. anonymous
    • one year ago
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    yup

  3. anonymous
    • one year ago
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    now you know the relationship between csc and sin ?

  4. anonymous
    • one year ago
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    yeah reciprocals right?

  5. anonymous
    • one year ago
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    it's called inverse actually : csc(x)=1/sin(x)

  6. anonymous
    • one year ago
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    my bad

  7. anonymous
    • one year ago
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    now csc(2x)=1/sin(2x)

  8. anonymous
    • one year ago
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    now sin(2x)=sin(x+x) which is....

  9. anonymous
    • one year ago
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    sin(a+b)=...

  10. anonymous
    • one year ago
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    continue

  11. anonymous
    • one year ago
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    yeah I'm lost

  12. anonymous
    • one year ago
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    sin(a+b)=?

  13. anonymous
    • one year ago
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    you have a formula for this

  14. anonymous
    • one year ago
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    sin(a+b)=sin(a)cos(b)+sin(b)cos(a)

  15. anonymous
    • one year ago
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    now sin(x+x)=...

  16. anonymous
    • one year ago
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    sin(2x)

  17. anonymous
    • one year ago
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    use the formula mate

  18. anonymous
    • one year ago
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    replace x with a and x with b and add that sum

  19. anonymous
    • one year ago
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    sin(a+b) ??

  20. anonymous
    • one year ago
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    what?

  21. anonymous
    • one year ago
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    sin(2x)=2sinxcosx

  22. anonymous
    • one year ago
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    now

  23. anonymous
    • one year ago
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    your limit can be written in this form \[\lim_{x \rightarrow \pi}\frac{ 1 }{ 2\sin x \cos x }\]

  24. anonymous
    • one year ago
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    now replace x with pi and do the math...

  25. anonymous
    • one year ago
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    .027 ?

  26. anonymous
    • one year ago
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    thank you i got it

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