Graph the system of inequalities. Then use your graph to determine which points are solutions of the system.
x > 3
y ≤ 2x – 5
Choose all answers that are correct.
A.(4, –4)
B.(4, 8)
C.(5, 10)
D.(6, 0)
E.(6, –2)

- freemap

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- freemap

@undeadknight26

- undeadknight26

Do you know how to graph them?

- freemap

I think you say like since -5 is the y intercept you graph that at 0,-5. And go over 5 and 2 up for 2x. I think

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## More answers

- undeadknight26

Try desmos graphing.

- freemap

Whats desmos graphing?

- texaschic101

do you really have to graph...because this can be solved without graphing

- imqwerty

can u graph x=3
and y=2x-3 :)

- undeadknight26

You can plug and play but it says to graph lol.

- freemap

No, They just gave me answer choices @texaschic101

- texaschic101

than just plug your answer choices into the 2 inequalities and see which ones are true. Keep in mind, they both have to be true for it to be a solution.

- imqwerty

yes u can find the answer by pluggin in the options :)

- freemap

Do you like multipy and add to find the answer?

- texaschic101

Let me do the first one for you.....we will be using (4,-4)...x = 4 and y = -4
now lets begin..
x > 3....sub in 4 for x
4 > 3.....this is true
now we have to check it with the other inequality.
y <= 2x - 5....sub in 4 for x and -4 for y
-4 <= 2(4) - 5
-4 <= 8 - 5
-4 <= 3....this is also true
and since both are true, this is a solution
understand ?

- freemap

I do understand, this is kinda like what we did yesterday

- texaschic101

just be sure that both inequalities are true....because if you sub in your points and only one inequality is true, it is NOT a solution because they both have to be true

- freemap

Ok

- freemap

I will attempt to do the next one

- texaschic101

Because if you look at the first inequality x > 3....all of the answer choices are correct for this. So I would just check the answer choices with the 2nd inequality.

- freemap

ok, smart plan

- texaschic101

so y <= 2x - 5.......is (4,8) a solution ? Can you tell me ?

- freemap

I am working in out
8<=2(4)-5
8<8-5
8<3
8 is not less than 3 so false

- texaschic101

you are correct....and since (4,8) does not make BOTH inequalities true, then it is NOT a solution. Good job...way to go :)

- freemap

Thanks ok for the next one
10<2(5)-5
10<10-5
10<5
10 is not less than 5
10>3
Is true, but not for both equations. So False

- texaschic101

correct...(5,10) is not a solution

- freemap

Next one,
0<2(6)-5
0<12-5
0<7
0 is less than 7 so true
0>3
0 is not more than 3 so false
So false

- texaschic101

try again.....
x > 3
(6,0)...x = 6 and y = 0........do not get your x's and y's mixed up

- texaschic101

x > 3......x = 6
6 > 3...true
and (6,0) also makes the other inequality correct....so (6,0) IS a solution

- freemap

I'm sorry like you said got my x and y mixed up, helps to get a clean sheet of paper to lol

- texaschic101

lol...yes...that helps. To many numbers and letters mixed on one piece of paper will drive you insane

- freemap

lol, hopefully I'll get this one right
6>3
True 6 is more than 3
-2<2(6)-5
-2<12-5
-2<7
-2 is less than 7 so true
Both equations are true

- texaschic101

you got it....(6,-2) is a solution.....nicely done :)

- freemap

Thanks you so A, D, E

- texaschic101

yep.....lol...I had to go back up and look...its A,D,E

- freemap

Thanks such a great help

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