A breeding group of beavers is introduced into a protected area. After t years the number of beavers in the area is modeled by the function N(t)= 54/0.35+0.68^t 1. How many beavers were initially introduced? 2. Estimate the number of beavers after 5 years. 3. Determine the change in the beaver population between t = 5 and t = 10. (Note: All answers are whole numbers.)

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A breeding group of beavers is introduced into a protected area. After t years the number of beavers in the area is modeled by the function N(t)= 54/0.35+0.68^t 1. How many beavers were initially introduced? 2. Estimate the number of beavers after 5 years. 3. Determine the change in the beaver population between t = 5 and t = 10. (Note: All answers are whole numbers.)

Mathematics
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The answers that I have so far are (I am not sure if I did them right): 1. N(t)= 54/0.35+0.68^0 = 40 2. N(t)= 54/0.35+0.68^5 = 109 3. I am not sure?
For initial result put t=0
question #1 you have to evaluate N(0)

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Other answers:

yup and for #2 put t=5
1. 40 2. 109 3. ?
as change is n(5) - n(10) put t= 5 and t=10 and subtract
yes! for third part we have to compute this: \[{N\left( 5 \right) - N\left( 0 \right) = ...?}\]
I am not sure exactly how to compute that what do I plug in?
is your formula like this: \[N\left( t \right) = \frac{{54}}{{0.35 + 0.68t}}\]
from 10 to 5 n(10) = 54/(.35+(.68^(10)))
@Michele_Laino that's how my formula is.
sorry ! Is it like below: \[\Large N\left( t \right) = \frac{{54}}{{0.35 + {{0.68}^t}}}\]
yes
yup ^ this power operator.
then if t=0, we have: \[\Large N\left( 0 \right) = \frac{{54}}{{0.35 + 1}} = ...?\]
40
correct!
if t=5, then we have: \[\Large N\left( 5 \right) = \frac{{54}}{{0.35 + {{0.68}^5}}} \cong 109\]
so do I just go 109-40=69?
nope i dont think so
for t=10, we have: \[\Large N\left( {10} \right) = \frac{{54}}{{0.35 + {{0.68}^{10}}}} \cong 145.5\]
3. Determine the change in the beaver population between t = 5 and t = 10. here t is 10 and 5 implies 145-109 =?
so you have to do this: \[\Large N\left( {10} \right) - N\left( 5 \right) = 145.5 - 109 = ...?\]
145.5-109=36.5
that's right!
yup in whole no.
yes! @AdityaOS is right!
So the answers are: 1. 40 2. 109 3. 36.5 but isn't 36.5 not in whole number
you can round off 36.5 to 37
oh ok thank you @Michele_Laino and @AdityaOS
:)

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