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anonymous
 one year ago
if NS bisects <QNR, find m<QNR
QNS is (6x57)
RNS is (2x+ 15)
anonymous
 one year ago
if NS bisects <QNR, find m<QNR QNS is (6x57) RNS is (2x+ 15)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I forgot how to do this. do I add the x and the subtact 15 from each side

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0Did you draw a picture?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0Did you see that angles QNS and RNS are a linear pair?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0Trick question. You should not see that because we are not told that.dw:1441039192569:dw Definition of bisector. What can we say about the measures of the two angles created by the bisection?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Haha good one, and I have no clue.

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0"BI" What might that mean?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0Bimonthly Bicycle Bifurcate Bisect

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0Right. And what does "bi" mean in this case?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dived into two parts

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0Two EQUAL parts. The measures of the two angles are equal. Now what? We are given the measures of the two angles.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes. (2x+15) and (6x15)

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0It says "57" above. Which is correct. Anyway, you are nearly done. 2x+15 = 6x15 Solve or x. This will not quite complete the assignment.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I add 6x and 2x and I get 8x. or do I subtract them???

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0No. You must solve using normal procedures. Don't get jumpy. Subtract 2x from both sides.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do you know if you subtract or add

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0You need to create zeros. 2x +15 = 6x  15 Subtract 2x 2x  2x +15 = 6x  2x  15 0 +15 = 4x  15 Or just 15 = 4x  15 Now, add 15. It should create zero, somewhere.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then aren't you left with 4x

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0You must be more careful. 15 = 4x  15 Add 15 15 + 15 = 4x  15 + 15 30 = 4x  0 30 = 4x Now, divide by 4. Be careful.
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