Let f(x)=2x^3-4x+1. Fill in the blank with the number of times the output value (y) occurs for input values of x between -3 and 3 (options listed in answer bank). Graph on your calculator in an appropriate window so you can count how many times.

- KJ4UTS

- chestercat

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- KJ4UTS

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- KJ4UTS

I am having a little trouble understanding what this question is asking me. Are there any graphing calculators online?

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## More answers

- KJ4UTS

Do they want me to plug those numbers into the formula?

- Michele_Laino

we have to use the graph of your function

- KJ4UTS

I don't know if the link will work but that's the graph I plugged in

- Michele_Laino

here is the procedure wit y=20 and y=-3:

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- Michele_Laino

you have to count the intersection points

- Michele_Laino

please I redraw the graph, please wait

- Michele_Laino

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- Michele_Laino

for example y=-3 (green horizontal line) give us only one intersection point between the vertical lines at x=-3 and x=3, so we have only one solution

- KJ4UTS

oh so all those numbers are on the y axis 20, -3, 2, -40, and 1

- Michele_Laino

yes!

- Michele_Laino

y=20 (blue horizontal line) gives us only one intersection point between the vertical lines at x=-3 and x=3, so, again, we have only one solution

- Michele_Laino

simlarly with others values y=2, -40, 1

- Michele_Laino

similarly*

- KJ4UTS

what graphing calculator is the one your using?

- Michele_Laino

it is "desmos":
https://www.desmos.com/calculator

- KJ4UTS

ok I going to try the other ones

- KJ4UTS

y=20 (one intersection point)
y=-3 (one intersection point)
This is what I got?
y=2 (three intersection point)
y=-40 (one intersection point)
y=-1(three intersection point)

- KJ4UTS

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- KJ4UTS

I did not get 4 anywhere.

- Michele_Laino

ok! correct!

- Michele_Laino

we are not able to get 4 intersection points, because your function is a polynomial of degree= 3, s, at maximum, we get three solutions

- Michele_Laino

so*

- KJ4UTS

ok thank you the desmos calculator is really helpful

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