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Testing123guest

  • one year ago

help plz

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  1. Testing123guest
    • one year ago
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  2. Michele_Laino
    • one year ago
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    hint: \[\Large 5 \times {10^6} \times 473 = \left( {5 \times 473} \right) \times {10^6} = ...?\]

  3. Testing123guest
    • one year ago
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    i dont know i am not good at this stuff

  4. Michele_Laino
    • one year ago
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    hint: \[\Large 5 \times 473 = 2365 \cong 2400 = 2.4 \times {10^3}\]

  5. Testing123guest
    • one year ago
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    2.4×10^3 is not one of the answers

  6. Michele_Laino
    • one year ago
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    you have to do this multiplication: \[\large 5 \times {10^6} \times 473 = \left( {5 \times 473} \right) \times {10^6} = \left( {2.4 \times {{10}^3}} \right) \times {10^6} = ...?\]

  7. Michele_Laino
    • one year ago
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    more precisely: \[\large 5 \times {10^6} \times 473 = \left( {5 \times 473} \right) \times {10^6} \cong \left( {2.4 \times {{10}^3}} \right) \times {10^6} = ...?\]

  8. Testing123guest
    • one year ago
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    2400000000

  9. Testing123guest
    • one year ago
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    @Michele_Laino plz man i need help

  10. Michele_Laino
    • one year ago
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    yes! correct! we can write that result using scientific notation as below: \[\large \begin{gathered} 5 \times {10^6} \times 473 = \left( {5 \times 473} \right) \times {10^6} \cong \left( {2.4 \times {{10}^3}} \right) \times {10^6} = \hfill \\ \hfill \\ = 2.4 \times {10^9} \hfill \\ \end{gathered} \]

  11. Michele_Laino
    • one year ago
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    \[\begin{gathered} 5 \times {10^6} \times 473 = \left( {5 \times 473} \right) \times {10^6} \cong \left( {2.4 \times {{10}^3}} \right) \times {10^6} = \hfill \\ \hfill \\ = 2.4 \times {10^9} \hfill \\ \end{gathered} \]

  12. Testing123guest
    • one year ago
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    thz man u rock

  13. Michele_Laino
    • one year ago
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    :)

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