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anonymous

  • one year ago

okay im back with more questions and more medals to give out nnesha is very good at helping ppl so if you have questions and shes on youll do wonderfully and that goes for jim but hes not one yet. okay back to the problem at hand. (-8+i) (-8-i) i got 64i - i bc i foiled btu they want this in standard form what did i do wrong?

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  1. Nnesha
    • one year ago
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    :P thanks haha :=)

  2. Nnesha
    • one year ago
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    show ur work plz :=)

  3. anonymous
    • one year ago
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    your welcome! I hope you get many medals :) |dw:1441041648467:dw| |dw:1441041814049:dw|

  4. Nnesha
    • one year ago
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    to foil two parentheses box method would be great/neat |dw:1441042176623:dw|i times -i = ??

  5. Nnesha
    • one year ago
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    when you multiply same bases you should `add` their exponents

  6. anonymous
    • one year ago
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    okay i remember here is rule a while ago but i cant remember it that well.

  7. Nnesha
    • one year ago
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    alright so when we multiply same bases we should add their exponents \[\huge\rm x^m \times x^n=x^{m+n}\]

  8. Nnesha
    • one year ago
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    i is same as i to the one power so \[\huge\rm i^1 \times i^1=??\]

  9. anonymous
    • one year ago
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    the thing i guess that is confusing me is the fact that my problem does not contain exponents. The i thing does sort of make sense.

  10. Nnesha
    • one year ago
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    no there is an exponent `invisible one`

  11. Nnesha
    • one year ago
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    i is same as i^1

  12. anonymous
    • one year ago
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    okay

  13. anonymous
    • one year ago
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    so my negative i should be squared then your suposed to take (-1) (-i) i^2

  14. anonymous
    • one year ago
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    to make it with out its exponent

  15. Nnesha
    • one year ago
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    multiply i times i which is i^2 and i^2 =what ?

  16. anonymous
    • one year ago
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    i?

  17. Nnesha
    • one year ago
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    \[\large\rm i=\sqrt{-1}~~~~~~~so~~i^2=?\]

  18. anonymous
    • one year ago
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    so is it just -1? im still confused

  19. Nnesha
    • one year ago
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    yes right i^2=-1

  20. Nnesha
    • one year ago
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    you should remember 4 cycle of i \[\rm i=\sqrt{-1}\]\[\rm i^2=-1\] \[\rm i^3=-i\]\[\rm i^4=1\]

  21. anonymous
    • one year ago
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    so the answer should be 63?

  22. Nnesha
    • one year ago
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    if you know that then you can find i^999

  23. Nnesha
    • one year ago
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    nope

  24. anonymous
    • one year ago
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    i have no clue

  25. Nnesha
    • one year ago
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    it's |dw:1441043195360:dw| i times -1 forgot the negative

  26. Nnesha
    • one year ago
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    i times -i**

  27. Nnesha
    • one year ago
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    |dw:1441043278896:dw| i^2=-1 now distribute -(-1) then combine them

  28. Nnesha
    • one year ago
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    you gotta be careful about signs especially negative

  29. anonymous
    • one year ago
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    so 64 -(-1) = 64+1 = 65

  30. Nnesha
    • one year ago
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    \(\huge\color{green}{\checkmark}\)

  31. Nnesha
    • one year ago
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    great job!

  32. anonymous
    • one year ago
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    okay let me check it on my math lab

  33. anonymous
    • one year ago
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    you rock!!

  34. Nnesha
    • one year ago
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    :=) i like to work with somone who `really` wants to learn not just waiting for the answer so great job!

  35. anonymous
    • one year ago
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    thank you i used to be really good at math but since ive graduated its like ive lost almost everything but your refreshing my memory! (;

  36. Nnesha
    • one year ago
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    aww congrats! so are u going to take calculus one right ? good luck!

  37. anonymous
    • one year ago
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    nope lol im not in calculus i wish i knew calculus it would give me an advantage im in a math prep for college and then im in an actual college class that will adventually teach us calculus.

  38. anonymous
    • one year ago
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    at GGC

  39. Nnesha
    • one year ago
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    ohh okay

  40. anonymous
    • one year ago
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    ill be on later im gonna attempt to work on some of these by my self now the foil with the i is still a bit confusing though.

  41. anonymous
    • one year ago
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    the prob was (2+7i)^2 and they want me to use foil i got 4+77i which is not correct

  42. Nnesha
    • one year ago
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    (2+7i)^2 is same as (2+7i)(2+7i) now foil!

  43. anonymous
    • one year ago
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    okay im gonna go step by step with how i got 4+77i

  44. Nnesha
    • one year ago
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    alright so plz show ur work :=)

  45. anonymous
    • one year ago
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    |dw:1441044467368:dw|

  46. Nnesha
    • one year ago
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    |dw:1441044870538:dw|

  47. anonymous
    • one year ago
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    okay so instead it is 4+28i+49 then i would add the 4+49 = 53+28i?

  48. Nnesha
    • one year ago
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    no it's \[\huge\rm 4+28i+49i^2=4+28i+49(-1)\] 49 is positive before u distribute by negative on

  49. anonymous
    • one year ago
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    ah okay the signs get me again. then this should be -45+28i

  50. Nnesha
    • one year ago
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    looks good!

  51. anonymous
    • one year ago
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    okay one moment

  52. Nnesha
    • one year ago
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    okay

  53. anonymous
    • one year ago
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    your name proves you well you are definatly the human calculator (: it was correct

  54. Nnesha
    • one year ago
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    haha thanks for the compliment lol there are like 1000+ users who really good at math i'm just fine :3

  55. anonymous
    • one year ago
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    Lol well your help has worked wonders i will talk to you again later. Thank you!!

  56. Nnesha
    • one year ago
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    okay :D

  57. Nnesha
    • one year ago
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    & my pleasure :=)

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