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anonymous
 one year ago
An analysis of a 4.2gram sample of a compound is found to contain 54.76 percent sodium (Na) and 45.24 percent fluorine (F). Determine the empirical formula of the compound.
Na2F
NaF2
NaF
Na2F2
anonymous
 one year ago
An analysis of a 4.2gram sample of a compound is found to contain 54.76 percent sodium (Na) and 45.24 percent fluorine (F). Determine the empirical formula of the compound. Na2F NaF2 NaF Na2F2

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alphabeta
 one year ago
Best ResponseYou've already chosen the best response.1If you think in terms of the hypothetical 100g sample, then you can calculate it like this: Number of moles (n) = mass (m) / molecular mass (Mr). You can find the molecular mass formula by looking in the periodic table. So; n(Na) = 54.76/22.99 = 2.381905... mol n(F) = 45.24/19.00 = 2.381052... mol Na has the smallest number of moles calculated and we will therefore divide each mole value on this smallest value, like this: Na: 2.381905... mol/2.381905... mol = 1 F: 2.381052... mol/2.381905... mol \[\approx 1\] So the empirical formula will then be: NaF
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