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Victoriaf16

  • one year ago

Write the equation of the line that passes through (1,5) and (-2,14) in slope-intercept form. Please help!!! thank you.

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  1. anonymous
    • one year ago
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    do you know the formula that is used to create a straight line by using two points ?

  2. Victoriaf16
    • one year ago
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    @esamalaa is it y2-y1/x2-x1?

  3. anonymous
    • one year ago
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    that is equal to? what is the other side of equation?

  4. anonymous
    • one year ago
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    slope-intercept form:\[y=mx+b\]where m is the slope and b is the y-intercept. you need to find the value of these or find another equation for the line that goes through your points and then solve that equation for y to get it into slope-intercept form.

  5. anonymous
    • one year ago
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    what you gave is the formula for finding the slope

  6. Victoriaf16
    • one year ago
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    I'm so confused. I hate algebra.

  7. anonymous
    • one year ago
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    yea if she used this formula and then rearrange the equation to get the slope-intercept formula

  8. anonymous
    • one year ago
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    take a breath, relax and open your mind... i will help you. don't hate on algebra. a bad attitude never tkaes you anywhere good! you ready?

  9. Victoriaf16
    • one year ago
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    Yes.

  10. anonymous
    • one year ago
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    |dw:1441047546354:dw| here are your points... connect them with a straight line

  11. Victoriaf16
    • one year ago
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    unfortunately I can't even see your graph, half of it is cut out. :/

  12. anonymous
    • one year ago
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    point-slope form:\[y-y_1=m \left( x-x_1 \right)\]if you solve for y you get:\[y=mx-mx_1+y_1 \Rightarrow y=mx+\left( y_1-mx_1 \right) \Rightarrow \left(y_1-mx_1\right) = b\] \[m=\frac{ y_2-y_1 }{ x_2-x_1 }\]\[\left( x_1, y_1 \right) \text{ and } \left( x_2, y_2 \right) \text{ are points}\]

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