Studying for a test and don't remember how to do this. Write the standard equation of the circle with center (-3, 5) and a diameter of 14. (x + 3)2 + (y – 5)2 = 49 (x + 3)2 + (y – 5)2 = 7 (x – 5)2 + (y + 3)2 = 49 (x – 3)2 + (y + 5)2 = 196

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Studying for a test and don't remember how to do this. Write the standard equation of the circle with center (-3, 5) and a diameter of 14. (x + 3)2 + (y – 5)2 = 49 (x + 3)2 + (y – 5)2 = 7 (x – 5)2 + (y + 3)2 = 49 (x – 3)2 + (y + 5)2 = 196

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\[\huge\rm (x-h)^2+(y-k)^2=r^2\] standard form equation of the circle where (h,k) is the center and r=radius remember radius is half of diameter
So is it B?

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Other answers:

if diameter is 14 then radius would be ?
7
\[\huge\rm (x-h)^2+(y-k)^2=r^\color{Red}{2}\] yes right so now look at the equation it's r^squared
So it would be 49
yes right
So it would be A?
i think so.:=)
Thank you so much!!(:

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