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anonymous

  • one year ago

Studying for a test and don't remember how to do this. Write the standard equation of the circle with center (-3, 5) and a diameter of 14. (x + 3)2 + (y – 5)2 = 49 (x + 3)2 + (y – 5)2 = 7 (x – 5)2 + (y + 3)2 = 49 (x – 3)2 + (y + 5)2 = 196

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  1. anonymous
    • one year ago
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    @Hero @dan815 @Nnesha @e.mccormick

  2. Nnesha
    • one year ago
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    \[\huge\rm (x-h)^2+(y-k)^2=r^2\] standard form equation of the circle where (h,k) is the center and r=radius remember radius is half of diameter

  3. anonymous
    • one year ago
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    So is it B?

  4. Nnesha
    • one year ago
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    if diameter is 14 then radius would be ?

  5. anonymous
    • one year ago
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    7

  6. Nnesha
    • one year ago
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    \[\huge\rm (x-h)^2+(y-k)^2=r^\color{Red}{2}\] yes right so now look at the equation it's r^squared

  7. anonymous
    • one year ago
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    So it would be 49

  8. Nnesha
    • one year ago
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    yes right

  9. anonymous
    • one year ago
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    So it would be A?

  10. anonymous
    • one year ago
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    @Nnesha

  11. Nnesha
    • one year ago
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    i think so.:=)

  12. anonymous
    • one year ago
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    Thank you so much!!(:

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