## anonymous one year ago Studying for a test and don't remember how to do this. Write the standard equation of the circle with center (-3, 5) and a diameter of 14. (x + 3)2 + (y – 5)2 = 49 (x + 3)2 + (y – 5)2 = 7 (x – 5)2 + (y + 3)2 = 49 (x – 3)2 + (y + 5)2 = 196

1. anonymous

@Hero @dan815 @Nnesha @e.mccormick

2. Nnesha

$\huge\rm (x-h)^2+(y-k)^2=r^2$ standard form equation of the circle where (h,k) is the center and r=radius remember radius is half of diameter

3. anonymous

So is it B?

4. Nnesha

if diameter is 14 then radius would be ?

5. anonymous

7

6. Nnesha

$\huge\rm (x-h)^2+(y-k)^2=r^\color{Red}{2}$ yes right so now look at the equation it's r^squared

7. anonymous

So it would be 49

8. Nnesha

yes right

9. anonymous

So it would be A?

10. anonymous

@Nnesha

11. Nnesha

i think so.:=)

12. anonymous

Thank you so much!!(: