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anonymous
 one year ago
Studying for a test and don't remember how to do this.
Write the standard equation of the circle with center (3, 5) and a diameter of 14.
(x + 3)2 + (y – 5)2 = 49
(x + 3)2 + (y – 5)2 = 7
(x – 5)2 + (y + 3)2 = 49
(x – 3)2 + (y + 5)2 = 196
anonymous
 one year ago
Studying for a test and don't remember how to do this. Write the standard equation of the circle with center (3, 5) and a diameter of 14. (x + 3)2 + (y – 5)2 = 49 (x + 3)2 + (y – 5)2 = 7 (x – 5)2 + (y + 3)2 = 49 (x – 3)2 + (y + 5)2 = 196

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Hero @dan815 @Nnesha @e.mccormick

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm (xh)^2+(yk)^2=r^2\] standard form equation of the circle where (h,k) is the center and r=radius remember radius is half of diameter

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1if diameter is 14 then radius would be ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm (xh)^2+(yk)^2=r^\color{Red}{2}\] yes right so now look at the equation it's r^squared

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much!!(:
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