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KJ4UTS
 one year ago
A breeding group of beavers is introduced into a protected area. After t years the number of beavers in the area is modeled by the function
N(t)= 54/0.35+0.68^t
1. How many beavers were initially introduced?
2. Estimate the number of beavers after 5 years.
3. Determine the change in the beaver population between t = 5 and t = 10.
(Note: All answers are whole numbers.)
KJ4UTS
 one year ago
A breeding group of beavers is introduced into a protected area. After t years the number of beavers in the area is modeled by the function N(t)= 54/0.35+0.68^t 1. How many beavers were initially introduced? 2. Estimate the number of beavers after 5 years. 3. Determine the change in the beaver population between t = 5 and t = 10. (Note: All answers are whole numbers.)

This Question is Closed

KJ4UTS
 one year ago
Best ResponseYou've already chosen the best response.0I think that the answers are (I just want to make sure): 1. 40 2. 109 3. 36.5 or 37 I think would be a whole number

KJ4UTS
 one year ago
Best ResponseYou've already chosen the best response.0N(t)= 54/0.35+0.68^0 = 40 N(t)= 54/0.35+0.68^5 = 109

KJ4UTS
 one year ago
Best ResponseYou've already chosen the best response.0I did the question and got partial points and would like to know where I went wrong?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0You have written \(N(t) = \dfrac{54}{0.35} + 0.68^{t}\). This appears not to be what you intend. Please write clearly.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes the first two are correct. For the third, it looks like you found N(10) instead of the calculating the rate of change

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0rate of change = [N(10)  N(5)] / (10  5)

KJ4UTS
 one year ago
Best ResponseYou've already chosen the best response.0@tkhunny sorry its N(t)= 54/(0.35+0.68^t)

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0So much better. Notation matters. Be careful.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0misread that. The don't want the rate of change, just the change. N(10)  N(5) is what you're asked for.

KJ4UTS
 one year ago
Best ResponseYou've already chosen the best response.0how do I use N(10)  N(5) do I plug something in?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, you plug in 5 and 10 for t. This is what you had above. N(t)= 54/(0.35+0.68^5) = 109 The N(t) should be N(5) because you substituted 5 for t. This is correct N(5)= 54/0.35+0.68^5 = 109.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So plug in 10 for t to find N(10)

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0That's N(10). What else would you do to find a change or difference?

KJ4UTS
 one year ago
Best ResponseYou've already chosen the best response.0I am not sure? I thought it would be 145109?

KJ4UTS
 one year ago
Best ResponseYou've already chosen the best response.0if I just do 145109=36 before I got 36.5 and rounded it to 37 and I got partial points maybe its just 36
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