anonymous
  • anonymous
Can you help me with 1.65?
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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anonymous
  • anonymous
@toxicsugar22 do you know?
anonymous
  • anonymous
@aaronq can you help?

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aaronq
  • aaronq
You just have to use the formula written there at the bottom
anonymous
  • anonymous
i understand that, but which is the T.V and the E.V??? that's what i don't understand @aaronq
aaronq
  • aaronq
true value and experimental value. Did they not give you these?
anonymous
  • anonymous
what's in the picture is what we got
anonymous
  • anonymous
do you want the full question?
aaronq
  • aaronq
really? maybe they want you to assume that the body temp is 37 Celsius
aaronq
  • aaronq
but yeah, post the question
anonymous
  • anonymous
it said body temp was 38.9 C
aaronq
  • aaronq
was that supposed to be the measured temperature?
anonymous
  • anonymous
The medicinal thermometer commonly used in the homes can be read (+or-) 0.1F, whereas those in the doctor's office may be accurate to (+or-) 0.1C, express the percent error expected from each of these thermometers in measuring a person's body temperature of 38.9C.
aaronq
  • aaronq
ohh okay. So the true value is 38.9 C and the largest possible error is \(\pm0.1~^oC\) So \(\sf percent~error =\dfrac{|true-experimental|}{true}*100\%\) note that the absolute value bars and how it wont matter if you add or subtract 0.1 C from the value. For celsius it's: \(\sf percent~error =\dfrac{|38.9^oC-39~^oC|}{38.9^oC}*100\%\)
aaronq
  • aaronq
Do the same for fahrenheit
anonymous
  • anonymous
what would the exp. be for F? 102.02 is true. so would exp. be 102.01?
aaronq
  • aaronq
102.02 F +0.1 F = 102.12 F
aaronq
  • aaronq
or 101.92
anonymous
  • anonymous
i'm getting .0980% (sorry it took so long, i got a phone call) @aaronq
aaronq
  • aaronq
yep, that seems good, i would round to 0.1 % though
anonymous
  • anonymous
Ok thank you!
aaronq
  • aaronq
no problem!

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