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## anonymous one year ago Find the point(s) of intersection: x^2 + y^2 = 25 xy = 12

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1. tkhunny

Have you considered substitution? From the second, x = 12/y -- Go!

2. anonymous

I tried, but I do not know how to evaluate 144/y^2 + y^2 = 25

3. anonymous
4. anonymous

$\frac{y^4+144}{y^2}=25$ $y^4+144=25y^2$ $y^4-25y^2+144=0$

5. tkhunny

What did you try? Can you solve 144/x+ x = 25?

6. anonymous

From y^4 - 25^2 + 144 = 0 would you factor? If so, how?

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