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anonymous

  • one year ago

Find and simplify each of the following assuming h does not equal 0.

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  1. anonymous
    • one year ago
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    (a) f(x+h) (b) f (x+h)- f(x) |dw:1441057778984:dw|

  2. anonymous
    • one year ago
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    (b) f(x+h) - f (x) ---> 4 (x+h)^2-7 (x+h)+6-4x^2 From here, I am not sure what to do.

  3. anonymous
    • one year ago
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    (a) f (x+h) ---> 4 (x+h)^2- 7 (x+h) +6 4 (x^2+2xh+h^2)-7 (x+h) +6 4x^2+8xh+4h^2-7x-7h+6 I know this is correct.

  4. anonymous
    • one year ago
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    With (b) and (c), I just need help formatting the problem correctly.

  5. Nnesha
    • one year ago
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    what's f(x)= ?

  6. anonymous
    • one year ago
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    f(x) = 4x^2-7x+6

  7. anonymous
    • one year ago
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    is this algebra?

  8. Nnesha
    • one year ago
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    alright substitute all x for (x+h)

  9. Nnesha
    • one year ago
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    ohh wait i'll check ur work

  10. anonymous
    • one year ago
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    It is functions, I'm reviewing for calc.

  11. anonymous
    • one year ago
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    So, yeah, algebra. :]

  12. anonymous
    • one year ago
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    pre-calculus

  13. Nnesha
    • one year ago
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    \[\huge\rm { 4x^2+8xh+4h^2-7x-7h+6 }\] this is correct

  14. anonymous
    • one year ago
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    Thank you.

  15. anonymous
    • one year ago
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    I'm having trouble for formatting (b) and (c).

  16. anonymous
    • one year ago
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    *with

  17. anonymous
    • one year ago
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    woah this is harder than i thought

  18. Nnesha
    • one year ago
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    \[\huge\rm \frac{ \color{reD}{ f(x+h)}-\color{green}{f(x)} }{ h}\] substitute f(x) for 4x^2-7x+6 and replace f(x+h) with 4x^2+8xh+4h^2-7x-7h+6

  19. Nnesha
    • one year ago
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    \[\large\rm \frac{ \color{Red}{ 4x^2+8xh+4h^2-7x-7h+6 }-\color{green}{(4x^2-7x+6) }}{ h }\] solve the numerator

  20. anonymous
    • one year ago
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    Oh! I understand. I'm so slow. 8xh+4h^2-7h

  21. Nnesha
    • one year ago
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    what would be the next step ?

  22. anonymous
    • one year ago
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    I'm not sure. Would we rewrite the answer correctly? If not, I don't know.

  23. Nnesha
    • one year ago
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    no that's right

  24. anonymous
    • one year ago
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    Like 4h^2+8xh-7h?

  25. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Wondergiirl Oh! I understand. I'm so slow. 8xh+4h^2-7h \(\color{blue}{\text{End of Quote}}\) this is perfect now what is common in all 3 terms ?

  26. anonymous
    • one year ago
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    Oh okay.

  27. Nnesha
    • one year ago
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    take out the common factor

  28. anonymous
    • one year ago
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    Would we take out h?

  29. Nnesha
    • one year ago
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    yep!

  30. anonymous
    • one year ago
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    Awesome! Thank you so much!

  31. Nnesha
    • one year ago
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    got it ? what's the final answer ?

  32. anonymous
    • one year ago
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    8x+9?

  33. Nnesha
    • one year ago
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    who kidnapped 4 ?? what happened to -7?

  34. anonymous
    • one year ago
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    I'm sorry. I meant 8x+4h-7.

  35. Nnesha
    • one year ago
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    yes right! it's okay great job!!

  36. anonymous
    • one year ago
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    Good Job :D

  37. Nnesha
    • one year ago
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    i wish u all the best! i hope you do well n calculus class :=)

  38. anonymous
    • one year ago
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    Thank you, both of you! :D

  39. Nnesha
    • one year ago
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    my pleasure :=)

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