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\[x _{f}=x _{0}+vt+\frac{ 1 }{ 2 }at^2\]

What do I use as acceleration? I know that the answer is -1.0 m, I just do not see it yet

Acceleration unit is m/s^2.
What makes you think you know the answer?
I solved it and it was not 1

nevermind, I got it. .32 m/s^2

I was looking at the other problem for some reason, this one i did get with the formula :) Thanks!

Ah, I see.
Nice job
No problem!

I thought I had copied the other problem here that I cant figure out haha

Oh no wonder.
Actually the answer is -0.33 not positive 0.32.
Forgot to tell you

Nope, the first formula is -0.33 m/s^2
The second formula is 0.33m/s^2

I write even the simplest thing on the notes, so that when going back I know where things came from. Even if I can do it in my head..... I know its long sorry

Yes it is better and way faster. I did it both ways and I always got .32 m/s^2

Which formula?
Mines or yours?

yours... here is what I did with yours,

Yea, it is a shortcut.
That is why they made it separate formula.