A particle confined to motion along the x-axis moves with constant acceleration from
x = 2.0 m
to
x = 8.0 m
during a 2.5-s time interval. The velocity of the particle at
x = 8.0 m
is 2.8 m/s. What is the acceleration during this time interval?

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\[x _{f}=x _{0}+vt+\frac{ 1 }{ 2 }at^2\]

What do I use as acceleration? I know that the answer is -1.0 m, I just do not see it yet

Acceleration unit is m/s^2.
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