Please help!! calc ab
If f(x) is differentiable for the closed interval [−1, 4] such that f(−1) = −3 and f(4) = 12, then there exists a value c, −1< c < 4 such that
f '(c) = 3
f '(c) = 0
f(c) = −15
f (c) = 3
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If f(x) = ∣(x2 − 10)(x2 + 1)∣, how many numbers in the interval 0 ≤ x ≤ 2.5 satisfy the conclusion of the mean value theorem?
None
One
Two
Three

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have you tried seeing if you can apply mean value theorem to question 1 ?

I understand that i tis mean value theorem but i didn't get the same answer as them

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