## anonymous one year ago The point on the terminal side of θ = -3 pi/ 4 that has an x coordinate of -1

1. anonymous

2. anonymous

$x=r \cos \theta$ $r \cos \frac{ -3 \pi }{ 4 }=-1$ $r \cos \frac{ 3 \pi }{ 4 }=-1$ $r \cos \left( \pi-\frac{ \pi }{ 4 } \right)=-1$ $-r \cos \frac{ \pi }{ 4 }=-1$ $r*\frac{ 1 }{\sqrt{2} }=1,r=\sqrt{2}$ $y=r \sin \theta=\sqrt{2}\sin \frac{ -3 \pi }{ 4 }=-\sqrt{2}\sin \frac{ 3\pi }{ 4 }=-\sqrt{2}\sin \left( \pi-\frac{ \pi }{ 4 } \right)$ $or~y=-\sqrt{2}\sin \frac{ \pi }{ 4 }=-\sqrt{2}*\frac{ 1 }{\sqrt{2} }=-1$ so point is (-1,-1)

3. triciaal

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