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anonymous
 one year ago
find the limit as x approaches 1 of abs(x1)/x1
anonymous
 one year ago
find the limit as x approaches 1 of abs(x1)/x1

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 1}\frac{ \left x1 \right }{ x1 }\]

random231
 one year ago
Best ResponseYou've already chosen the best response.1okay what is the first thing you check for when you solve a limit?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@random231 you plug it in to see if you get 0/0

random231
 one year ago
Best ResponseYou've already chosen the best response.1nope dinamix i dont think you got it!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@random231 and if so you have to simplify

random231
 one year ago
Best ResponseYou've already chosen the best response.1no clara the first thing you have to check whether the limit exists or not!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\large { \lim\limits_{x\to 1}\ \cfrac{x1}{x1}\implies \begin{cases} \lim\limits_{x\to 1^{\color{red}{ +}}}\ \cfrac{+(x1)}{x1} \\ \quad \\ \lim\limits_{x\to 1^{\color{red}{ }}}\ \cfrac{(x1)}{x1} \end{cases} }\)

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 1^+} = \frac{ x1 }{ x1 } = 1 \]

random231
 one year ago
Best ResponseYou've already chosen the best response.1that is you put in a value immediate to the left of 1 in one case and to the right in the other case. if both of them give the same value then the limit exists.

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0yup @ what i said @random231 its 1 and 1

random231
 one year ago
Best ResponseYou've already chosen the best response.1nope there cant be two values

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@dinamix if thats the case then doesn't the limit not exist? if theyre two different numbers?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0notice the values found for the two onesided limits they differ thus the twosided limit of \(\lim\limits_{x\to 1}\ \cfrac{x1}{x1}\impliedby \textit{does not exist}\)

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441065218850:dw this is graph of function now we understand everything i think i am right about my graph draw it @clara1223 , @random231
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