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nuccioreggie

  • one year ago

Convert 5.764764764 … to a rational expression in the form of a over b, where b ≠ 0. 5 and 764 over 999 5764 over 9999 5 and 764 over 99 5 and 999 over 764

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  1. nuccioreggie
    • one year ago
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    @peachpi help i think its B

  2. freckles
    • one year ago
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    \[x=5.764\overline{764} \\ \text{ multiply both sides by }1000 \\ 1000x=5.764 \overline{764} \\ \text{ now subtract} x \text{ 's value from }1000x \text{'s value }\]

  3. nuccioreggie
    • one year ago
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    so B

  4. freckles
    • one year ago
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    oops forgot to move the decimal

  5. freckles
    • one year ago
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    \[x=5.764\overline{764} \\ \text{ multiply both sides by }1000 \\ 1000x=5764. \overline{764} \\ \text{ now subtract} x \text{ 's value from }1000x \text{'s value }\]

  6. nuccioreggie
    • one year ago
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    OH OK SO ITS c

  7. freckles
    • one year ago
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    |dw:1441065633387:dw|

  8. nuccioreggie
    • one year ago
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    its C?

  9. freckles
    • one year ago
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    solve the equation for x to find out

  10. freckles
    • one year ago
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    err i'm dyslexic |dw:1441065756301:dw| but you should get the idea

  11. nuccioreggie
    • one year ago
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    so its A?

  12. nuccioreggie
    • one year ago
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    @freckles

  13. nuccioreggie
    • one year ago
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    @freckles itss A right

  14. freckles
    • one year ago
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    we can find out 1000x-x=? and 5764-5=?

  15. nuccioreggie
    • one year ago
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    5759

  16. freckles
    • one year ago
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    and 1000x-x=999x correct?

  17. freckles
    • one year ago
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    |dw:1441066119298:dw|

  18. nuccioreggie
    • one year ago
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    so it it B??????/

  19. freckles
    • one year ago
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    \[\frac{5759}{999}=\frac{5(999)+764}{999}=\frac{5(999)}{999}+\frac{764}{999}\]

  20. nuccioreggie
    • one year ago
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    OH I KNOW THE ANSWER ITS A thanks @freckles

  21. freckles
    • one year ago
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    lol yes you makes a lot of guesses

  22. nuccioreggie
    • one year ago
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    lol

  23. dan815
    • one year ago
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    |dw:1441066476932:dw|

  24. nuccioreggie
    • one year ago
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    Order the set of numbers from least to greatest: 2.71 repeating 71, 2 and 3 over 4, square root 5, 5 over 2 2.71 repeating 71, 2 and 3 over 4, square root 5, 5 over 2. square root 5, 5 over 2, 2.71 repeating 71, 2 3 over 4 5 over 2, square root 5, 2.71 repeating 71, 2 3 over 4 2 3 over 4, 2.71 repeating 71, 5 over 2, square root 5

  25. nuccioreggie
    • one year ago
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    @dan815

  26. dan815
    • one year ago
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    you can solve as that geometric series thing too if ud like

  27. nuccioreggie
    • one year ago
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    ok but can you tell me the last one i just put there please

  28. dan815
    • one year ago
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    rewrite the repeating one as a fractions

  29. dan815
    • one year ago
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    and square the numbers for example if a<sqrt(b) then a^2<b this still holds if we square both sides so we can use this property even thought we dont know what sqrt 5 exactly is

  30. nuccioreggie
    • one year ago
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    so itd D?

  31. nuccioreggie
    • one year ago
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    for the second question?

  32. nuccioreggie
    • one year ago
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    i ment B Sorry

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