Convert 5.764764764 … to a rational expression in the form of a over b, where b ≠ 0. 5 and 764 over 999 5764 over 9999 5 and 764 over 99 5 and 999 over 764

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Convert 5.764764764 … to a rational expression in the form of a over b, where b ≠ 0. 5 and 764 over 999 5764 over 9999 5 and 764 over 99 5 and 999 over 764

Mathematics
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@peachpi help i think its B
\[x=5.764\overline{764} \\ \text{ multiply both sides by }1000 \\ 1000x=5.764 \overline{764} \\ \text{ now subtract} x \text{ 's value from }1000x \text{'s value }\]
so B

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oops forgot to move the decimal
\[x=5.764\overline{764} \\ \text{ multiply both sides by }1000 \\ 1000x=5764. \overline{764} \\ \text{ now subtract} x \text{ 's value from }1000x \text{'s value }\]
OH OK SO ITS c
|dw:1441065633387:dw|
its C?
solve the equation for x to find out
err i'm dyslexic |dw:1441065756301:dw| but you should get the idea
so its A?
@freckles itss A right
we can find out 1000x-x=? and 5764-5=?
5759
and 1000x-x=999x correct?
|dw:1441066119298:dw|
so it it B??????/
\[\frac{5759}{999}=\frac{5(999)+764}{999}=\frac{5(999)}{999}+\frac{764}{999}\]
OH I KNOW THE ANSWER ITS A thanks @freckles
lol yes you makes a lot of guesses
lol
|dw:1441066476932:dw|
Order the set of numbers from least to greatest: 2.71 repeating 71, 2 and 3 over 4, square root 5, 5 over 2 2.71 repeating 71, 2 and 3 over 4, square root 5, 5 over 2. square root 5, 5 over 2, 2.71 repeating 71, 2 3 over 4 5 over 2, square root 5, 2.71 repeating 71, 2 3 over 4 2 3 over 4, 2.71 repeating 71, 5 over 2, square root 5
you can solve as that geometric series thing too if ud like
ok but can you tell me the last one i just put there please
rewrite the repeating one as a fractions
and square the numbers for example if a
so itd D?
for the second question?
i ment B Sorry

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